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Anit [1.1K]
3 years ago
5

What is the factored form of the polynomial?

Mathematics
1 answer:
Firdavs [7]3 years ago
8 0

Answer:

(x-3) (x-9) or (x-9) (x-3)

Step-by-step explanation:

1) what * what=27

and what+what=-12

factors of 27: 9,3  -9,-3  1,27 -1,27

-9+-3=-12

hence -9 and -3 are our factors

(substitute -9 and -3 in place of -12)

x^2-9x-3x+27

split into two groups:

x^2-9x

(both have a gcf of x)

x(x-9)

and

-3x+27

(both have a gcf of "-3"

-3(x-9)

take the numbers OUTSIDE the parantheses and put them in a bracket:

(x-3) (x-9)

Hope this helps!

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Step-by-step explanation:

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3 years ago
What is a cubic polynomial function with zeros 3,3 and -3? show your work.​
Brums [2.3K]

Answer:

Cubic polynomial function with zeros 3,3 and -3 is \mathbf{x^3-3x^2-9x+27=0}

Step-by-step explanation:

We need to find a cubic polynomial function with zeros 3,3 and -3.

If zeros of polynomial are: 3,3,and -3

we can write:

x=3, x=3, x=-3

Or

We can write:

x-3=0, x-3=0, x+3=0

Now, we can write them as:

(x-3)(x-3)(x+3)=0

Multiplying the terms, we can find the polynomial:

(x-3)(x-3)(x+3)=0\\(x(x-3)-3(x-3))(x+3)=0\\(x^2-3x-3x+9)(x+3)=0\\(x^2-6x+9)(x+3)=0\\x(x^2-6x+9)+3(x^2-6x+9)=0\\x^3-6x^2+9x+3x^2-18x+27=0\\x^3-6x^2+3x^2+9x-18x+27=0\\x^3-3x^2-9x+27=0

So, cubic polynomial function with zeros 3,3 and -3 is \mathbf{x^3-3x^2-9x+27=0}

4 0
2 years ago
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