Answer:
Heating sample too rapidly may cause the thermometer reading to differ from the actual temperature of the heat source. Why is a finely powdered sample used in a melting point measurement? Particles may not pack well.
Step-by-step explanation:
I had An assignment question like this
Answer: 490 grams of the first alloy should be used.
30 grams of the second alloy should be used.
Step-by-step explanation:
Let x represent the weight of the first alloy in grams that should be used.
Let y represent the weight of the second alloy in grams that should be used.
A chemist has two alloys, one of which is 15% gold and 20% lead. This means that the amount of gold and lead in the first alloy is
0.15x and 0.2x
The second alloy contains 30% gold and 50% lead. This means that the amount of gold and lead in the second alloy is
0.3y and 0.5y
If the alloy to be made contains 82.5 g of gold, it means that
0.15x + 0.3y = 82.5 - - - - - - - - - - - -1
The second alloy would also contain 113 g of lead. This means that
0.2x + 0.5y = 113 - - - - - - - - - - - - -2
Multiplying equation 1 by 0.2 and equation 2 by 0.15, it becomes
0.03x + 0.06y = 16.5
0.03x + 0.075y = 16.95
Subtracting, it becomes
- 0.015y = - 0.45
y = - 0.45/- 0.015
y = 30
Substituting y = 30 into equation 1, it becomes
0.15x + 0.3 × 30 = 82.5
0.15x + 9 = 82.5
0.15x = 82.5 - 9 = 73.5
x = 73.5/0.15
x = 490
Answer: -2
Step-by-step explanation:
3+2= 5
4^2-5= 11
9-11= -2
Answer:
Answer C --> y = 1/3 sin(x)
Step-by-step explanation:
When you are finding the inverse of a function, you are trying to obtain the function that applied to the one given gives you as result EXACTLY "x".
You know that the function sin(x) is the inverse of Arcsin(x), because when you applied it as follows, you obtain x (by cancelling out Arcsin and "liberating" the argument inside it: "x") :

But in this case applying sin (x) to Arcsin (3x) will not render just x, because the argument that ARcsin is carrying is not just "x" but "3x":

So we need to divide by 3 as well in order to obtain just "x" after applying our inverse. The function that does such is the third one listed (C), sinc it also has a multiplicative 1/3 that will cancel the factor 3 we want to get rid of.