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Question is not proper, Proper question is given below.
There are some nickels, dimes, and quarters in a large piggy bank. For every 2 nickels, there are 3 dimes. For every 2 dimes, there are 5 quarters. There are 500 coins in all. How many nickels, dimes, and quarters are in the piggy bank? How much are the coins in the piggy bank worth all together?
Answer:
There are 80 nickels, 120 dimes and 300 quarters in the piggy bank.
The piggy bank is worth $91.
Step-by-step explanation:
Let Number of Nickels be represented by 'n'.
Let Number of Dimes be represented by 'd'.
Let of Quarters be represented by 'q'.
Now Given:
For every 2 nickels, there are 3 dimes.
2 n = 3 d
1 n = number of dimes.
We will use Unitary method to find the same.
Number of 1 dimes d =
Also Given:
For every 2 dimes, there are 5 quarters.
2 d = 5 q
1 d = number of quarters
We will use Unitary method to find the same.
Number of 1 quarter q =
Also Given:
Total Number of coins = 500
Now d =
AND q =
So Substituting the values we get;
Taking LCM we get making denominator as 4.
Hence number of Nickels n = 80
Number of Dimes d =
Number of Quarters q =
Hence There are 80 nickels, 120 dimes and 300 quarters in the piggy bank.
Now we know that;
1 nickel = $0.05
so 80 nickels =
1 dime = $0.1
so 120 dimes =
1 quarter = $0.25
so 300 quarters =
So Total money = $4+$12+$75 = $91
Hence the piggy bank is worth $91.