$f(x)=2x^2-10,\ g(x)=x+9\\\\(f+g)(x)=f(x)+g(x)\\\\\text{Substitute:}\\\\(f+g)(x)=(2x^2-10)+(x+9)=2x^2-10+x+9=2x^2+x+(-10+9)\\\\(f+g)(x)=2x^2+x-1\\\\(f+g)(x)(5)\to\text{put x = 5 to the equation of the function:}\\\\(f+g)(5)=2(5^2)+5-1=2(25)+5-1=50+5-1=54$

8 0

3 years ago

Which of the following is not a Pythagorean triple?

Ierofanga [76]

Answer:

(7, 24, 26)

Step-by-step explanation:

A Pythagorean triple must have an odd number of even numbers. The triple (7, 24, 26) is not a Pythagorean triple.

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Additional comment

For an odd integer n, a triple can be formed as ...

(n, (n²-1)/2, (n²+1)/2)

That is, the following will be Pythagorean triples.

(3, 4, 5)
(5, 12, 13)
(7, 24, 25)
(9, 40, 41)
(11, 60, 61)

Another series involves even numbers and numbers separated by 2:

(2n, n²-1, n²+1)

(8, 15, 17)
(12, 35, 37)
(16, 63, 65)

In this list, if n is not a multiple of 2, the triple will be a multiple of one from the odd-number series.

It is a good idea to remember a few of these, as they tend to show up in Algebra, Geometry, and Trigonometry problems.

8 0

2 years ago