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Scilla [17]
3 years ago
7

In the triangle below, calculate the value of x.

Mathematics
1 answer:
ivanzaharov [21]3 years ago
4 0
Hope this helps you..!!.!!!!

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Solve Angle B please
kvv77 [185]

Answer:

x = 9

Angle B = 40°

Step-by-step explanation:

Angle A = Angle B

5x-5=3x+13

5x-3x=13+5

2x=18

x=18/2=9

Angle B = 3x + 13 = 3(9) + 13 = 27 +13 = 40°

Hope this helps

3 0
3 years ago
The slope of a line that contains the points (3,16) and (5, 20) is two. Find b, the y-intercept of this line.
OLEGan [10]

Answer:

[0, 10]

Step-by-step explanation:

Plug the coordinates into the Slope-Intercept Formula. It does not matter which ordered pair you choose:

20 = 2[5] + b

10

10 = b

y = 2x + 10

__________________________________________________________

16 = 2[3] + b

6

10 = b

y = 2x + 10

** You see? I told you it did not matter which ordered pair you choose because you will always get the exact same result.

I am joyous to assist you anytime.

7 0
3 years ago
Study the work shown below and compare the results to the product of –2i(6 – 7i). (0 – 2i)(6 – 7i) = (0)(6) + (0)(–7i) + (–2i)(6
In-s [12.5K]
-2i (6 - 7i)
 The first thing we must do is to solve this product and then compare it with the work shown.
 Resolving we have
 -2i (6 - 7i)
 (-2i) * (6) + (-2i) * (- 7i)
 -12i + 14i ^ 2
 -12i - 14
 Comparing, we can say that the products are the same.
 answer:
 the products are the same.
3 0
3 years ago
Read 2 more answers
21 is 70% of what number?
Vilka [71]
20% of 90 is 18. Try to turn 20% into a fraction it helps solve it. 

3 0
3 years ago
Read 2 more answers
The slope-intercept form of the equation of a line that passes through point (-2, -13) is y = 5x - 3. What is the point-
Alona [7]

y = \stackrel{\stackrel{m}{\downarrow }}{5}x-3\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}

well, what's the equation of a line whose slope is 5 and passes through (-2 , -13) ?

(\stackrel{x_1}{-2}~,~\stackrel{y_1}{-13})\qquad \qquad \stackrel{slope}{m}\implies 5 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-13)}=\stackrel{m}{5}(x-\stackrel{x_1}{(-2)})\implies y+13=5(x+2)

8 0
2 years ago
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