Type the expression as radicals 5/y2

1 answer:

Nadusha1986 [10]3 years ago

6 0

$\bf \cfrac{5}{y^2}\qquad 
\begin{cases}
\sqrt{25}=5\\
\sqrt{(y^2)^2}=y^2
\end{cases}\implies \cfrac{\sqrt{25}}{\sqrt{(y^2)^2}}\implies \cfrac{\sqrt{25}}{\sqrt{y^4}}\implies \sqrt{\cfrac{25}{y^4}}$

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