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Nikolay [14]
3 years ago
6

Which is the distance between points (0,3) to (5,-9) on the coordinate plane?

Mathematics
2 answers:
solong [7]3 years ago
7 0
Hi !

To calculate a distance between two points A and B of a coordinate plan, we use this specific fomula : \boxed{\boxed{AB=\sqrt{\left(x_B-x_A\right)^2+\left(y_B-y_A\right)^2}}}

So lets say we have two points : A(0, 3) and B (5, -9)

AB=\sqrt{\left(5-0\right)^2+\left(-9-3\right)^2}\\\\AB=\sqrt{5^2+(-12)^2}\\\\AB=\sqrt{25+144}\\\\AB=\sqrt{169}\\\\\boxed{AB=13}
pogonyaev3 years ago
4 0
This would be:-

square root [ (5-0)^2 + (-9 -3)^2) ]

= square root (  25 + 144)

= sqrt 169

= 13 Answer

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boyakko [2]

Answer: c) 14,871

Step-by-step explanation:

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8 0
3 years ago
Given that events A and B are independent with P(A) = 0.55 and P(B) = 0.72,
noname [10]

Answer:

Step-by-step explanation:

For independent events,

P(AB)=P(A)orP(B)

= P(A)uP(B)

=P(A)×P(B)

= 0.55×0.72

P(AB)=0.396

3 0
3 years ago
Colin invests £3900 into his bank account.
zloy xaker [14]

Answer:

Colin will have 421824 pennies after 2 years

Step-by-step explanation:

Given:

Amount invested in bank by Colin (P) = £3900

Rate of interest (r) = 4%

Time period (n) = 2 years

To find: Amount after 2 years (A)

Solution:

Formula for amount (A) is A=P\left ( 1+\frac{r}{100} \right )^n

A=3900\left ( 1+\frac{4}{100} \right )^2\\=3900\left ( 1+\frac{1}{25} \right )^2\\=3900\times \frac{26}{25}\times \frac{26}{25}\\=4218.24

As 1 pound = 100 pennies,

4218.24 pounds = 4218.24 × 100 = 421824 pennies

So,

Colin will have 421824 pennies after 2 years.

4 0
3 years ago
What would be this answer for the algebra thing
skad [1K]

Answer:

c. 4x + 20 = 140

Step-by-step explanation:

Perimeter = 140 feet

Width = L + 10

P = 2w + 2L

P = 2(L + 10) + 2L

P = 2L + 20 + 2L

P = 4L + 20

8 0
1 year ago
I need help if someone would? what is the correlation coefficient of the set of data? round your answer to the nearest thousandt
RSB [31]
0.98867. there are eight numbers, to get from one number to another use this
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