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Colt1911 [192]
3 years ago
12

The maturity value of a 30-day loan of $650 is $660. What is the annual simple interest rate (in percent) on this loan? Round to

the nearest tenth of a percent. Use 360 days in 1 year. (Enter a number.)
Mathematics
1 answer:
Zolol [24]3 years ago
7 0

Answer: the interest rate is 18.7%

Step-by-step explanation:

The formula for determining simple interest is expressed as

I = PRT/100

Where

I represents interest paid on the loan.

P represents the principal or amount taken as loan

R represents interest rate

T represents the duration of the loan in years.

From the information given,

P = 650

I = 660 - 650 = $10

T = 30 days. Converting to years,

T = 30/365 = 0.08219

10 = (650 × R × 0.08219)/100 = 0.5342R

R = 10/0.534 = 18.7% to the nearest tenth of a percent.

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prisoha [69]

Answer:

1 5/8 too short

Step-by-step explanation:

The cable on the truck is 18 and 3/8 ... to complete the fraction into a whole number we would need 5 more parts in order to complete the entire 8 parts of the fraction. This would make the cable a whole 19 feet. Since Ryan needs 20 ft, this would leave us needing 1 more foot. Therefore, the cable in the truck is

1 5/8 too short

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2 years ago
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What value does the 1 in the number 4,105.8
kirill115 [55]

Answer:

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Step-by-step explanation:

4 0
3 years ago
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In a study of automobile collision insurance costs, a random sample of n = 35 repair costs of front-end damage caused by hitting
laiz [17]

Answer: The maximum error = $105.76.

Step-by-step explanation:

Formula to find the maximum error:

E= z^*\dfrac{\sigma}{\sqrt{n}}

, where n= sample size.

\sigma = Population standard deviation

z*= Critical value(two-tailed).

As per given  , we have

\overline{x}=1438

n= 35

\sigma=269

For 98% confidence  , the significance level = 1-0.98=0.02

By z-table , the critical value (two -tailed) =z^* = z_{\alpha/2}=z_{0.01}=2.326

Now , the maximum error = E= (2.326)\dfrac{269}{\sqrt{35}}

E= (2.326)\dfrac{269}{5.9160797831}

E= (2.326)\times45.4692989044=105.761589252\pprox105.76

Hence, With 98% confidence level , the maximum error = $105.76.

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3 years ago
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