Question

Please can someone help; this is not cheating btw.

Answer 1

By determining the area of the square, we get $x^{2} +4x = 3.$

Step-by-step explanation:

Step 1:

The area of a square is given by squaring its side length.

The given squares side length is $(x+2)$ cm.

The area of a square $= a^{2} .$ Here a is the side length.

The area of the square is given as 7 cm².

Step 2:

Substituting the value of a in the equation, we get

$7 = (x+2)^{2} = x^{2} + 4x + 4.$

Taking the x values on one side and the constants on the other side, we get

$x^{2} +4x= 7-4 =3.$

So $x^{2} +4x = 3.$

So it has been proved.