All categories

3 years ago

If matrix A has dimensions 3 x 2 and matrix B has dimensions 3 x 2, can matrix A and matrix B be multiplied?

2 answers:

8 0

Matrix A has 3 rows, 2 columns
Matrix B has 3 rows, 2 columns

The number of columns in matrix A (which is 2) does not match up with the number of rows in matrix B (which is 3).

So the matrix multiplication A*B is undefined. We cannot multiply the matrices.

erik [133]3 years ago

6 0

Answer:

we can not multiply matrix A and B.

Step-by-step explanation:

We have been given that

dimension of matrix A = 3 x 2

dimension of matrix B = 3 x 2

Rule of multiplying two matrices:

Two matrix can be multiplied if the column of first matrix is equal to the row of second matrix.

column of first matrix = row of second matrix

Here, we have

Column of first matrix A = 2

Row of second matrix b = 3

Since,, column of matrix A ≠ Row of matrix B

Hence, we can not multiply matrix A and B.

You might be interested in

Nori had 2 2/12 bags of apples he used 1 5/12 bags of apples to make pies how many bags of apples does nori have left. 1. See an

diamong [38]

Answer:

Nori would have 9/12 of a bag left.

Step-by-step explanation:

she had 2 2/12 and she used 1 5/12 so you subtract them and get 9/12

6 0

2 years ago

Read 2 more answers

A machine in a chocolate factory is set to squirt out a predetermined amount of molten chocolate. When the machine is set to x,

frez [133]

Answer:

Sorry I need Points but I also need help

Step-by-step explanation:

3 0

3 years ago

In a downtown parking lot there are 5 times as many cars there as trucks. There are 12 trucks in the parking lot. How many cars

torisob [31]

12 * 5 = 60 Cars & 12 Trucks

7 0

2 years ago

Read 2 more answers

Simply the attached question

Finger [1]

Answer:

=x⁴−x³−14x²

Step-by-step explanation:

<h3>Let's simplify step-by-step.</h3>

x²(3x²+5x−4)−2x²(x²+3x+5)

<h3>Distribute:</h3>

=(x²)(3x²)+(x²)(5x)+(x²)(−4)+−2x⁴+−6x³+−10x²

=3x⁴+5x³+−4x²+−2x⁴+−6x³+−10x²

<h3>Combine Like Terms:</h3>

=3x⁴+5x³+−4x²+−2x⁴+−6x³+−10x²

=(3x⁴+−2x⁴)+(5x³+−6x³)+(−4x²+−10x²)

=x⁴+−x³+−14x²

=x⁴−x³−14x²

6 0

2 years ago

(a) Suppose you have 9 gold coins that look identical, but you also know one (and only one) of them is counterfeit. The counterf

alisha [4.7K]

Answer:

Step-by-step explanation:

You can split the coins into 3 groups, each of them has 3 coins. Weigh group 1 vs group 2, if one is lighter, that group has the fake coin. If both groups weigh the same, then group 3 has the fake coin.

Continue to split the group that has the fake coin into 3 groups, each group has 1 coin. Now apply the same procedure and we can identify the fake coin.

Total of scale usage is 2

b) if you have $3^n$ coins then you can apply the same approach and find the fake coin with just n steps. By splitting up to 3 groups each step, after each step you should be able to narrow down your suspected coin by 3 times.

Step 1: you narrow down to group of $\frac{3^n}{3} = 3^{n-1}$ coins

Step 2: you narrow down to group of $\frac{3^{n-1}}{3} = 3^{n-2}$ coins

Step 3: you narrow down to group of $\frac{3^{n-2}}{3} = 3^{n-3}$ coins

...

Step n: Step 1: you narrow down to group of $3^{n-n} = 3^0 = 1$ coin

8 0

3 years ago