If matrix A has dimensions 3 x 2 and matrix B has dimensions 3 x 2, can matrix A and matrix B be multiplied?

2 answers:

8 0

Matrix A has 3 rows, 2 columns
Matrix B has 3 rows, 2 columns

The number of columns in matrix A (which is 2) does not match up with the number of rows in matrix B (which is 3).

So the matrix multiplication A*B is undefined. We cannot multiply the matrices.

erik [133]3 years ago

6 0

Answer:

we can not multiply matrix A and B.

Step-by-step explanation:

We have been given that

dimension of matrix A = 3 x 2

dimension of matrix B = 3 x 2

Rule of multiplying two matrices:

Two matrix can be multiplied if the column of first matrix is equal to the row of second matrix.

column of first matrix = row of second matrix

Here, we have

Column of first matrix A = 2

Row of second matrix b = 3

Since,, column of matrix A ≠ Row of matrix B

Hence, we can not multiply matrix A and B.

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Answer:

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3 years ago

1.Parallelogram ACFD is split in two parts so that ABED and FEBC are congruent isosceles trapezoids. What are the measures of al

DiKsa [7]

Refer to the diagram shown below.

Because ACFD is a parallelogram, its opposite angles are equal. Therefore
x = m∠ACF = m∠BCF = 48°
Similarly,
y = m∠CAD = m∠CFD

The sum of the angles inside a parallelogram is 360°. Therefore
48° + x + y + y = 360°
Because x = 48°,
48° + 48° + 2y = 360°
2y = 360° - 96° = 264°
y = 132°

Because ABED and FEBC are congruent, therefore
y = m∠DAB = m∠CFE = 132°
x = m∠ADE = m∠FCB = 48°

Because FEBC is a parallelogram, the opposite angles are equal. Therefore
m∠CBE = m∠CFE = y = 132°
m∠BCF = m∠BEF = x = 48°

Answer:
The measures of all angles of trapezoid FEBC are
m∠BCF = 48°
m∠BEF = 48°
m∠CBE = 132°
m∠CFE = 132°