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Levart [38]
3 years ago
7

For any number n, if n2 is even, then n must be even. This means n being even is a ___________ condition for n2 being even.

Mathematics
2 answers:
Bas_tet [7]3 years ago
6 0

For any number n, if n2 is even, then n must be even. This means n being even is a <u>Necessary condition </u>for n2 being even.

Step-by-step explanation:

<u>Necessary Condition:</u>-A condition that says that the result has to be true but does not guarantee any kind of result.

Suppose we  assume that n is not even (i.e., it is odd)  

and show that n^2 is not even (i.e., it is odd).

n is odd then  you can write

   n = 2*k + 1 for an  integer k.

Then,  

  n^2 = 4*k^2 + 4*k + 1  

      = 2 * (2*k^2 + 2*k) + 1  

which is clearly odd.  

<u>This completes the proof that for any number n, if n2 is even, then n must be even</u>

Maslowich3 years ago
6 0

Answer:

The answer is necessary

Step-by-step explanation:

USA TP

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