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Darya [45]
3 years ago
11

Which of the following statements are true? check all that apply.

Mathematics
1 answer:
Margaret [11]3 years ago
5 0

<u>Answer:</u>

1 and 5 are correct.

<u>Step-by-step explanation:</u>

1. The mean is affected by outliers.  - TRUE

(the mean is the average so each of its values affect it.)

2. The mean is always a more accurate measure of center than the median. - FALSE

(the mean gives a better idea of the values while the the central values for normal distributions are described using the median value.)

3. Removing an outlier from a data set will cause the standard deviation to increase. - FALSE

(it makes the data set more normal by reducing the standard deviation, not increasing it. )

4. If the data set’s distribution is skewed, then 95%of its values will fall between two standard deviations of the mean. - FALSE

(the 68-95-99.9 rule works for the normal distribution, but the skewed distribution.)

5. If a data set’s distribution to skewed to the right, its mean will be larger than its median. - TRUE

(the mean is always pulled towards the direction of the skewness.)

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When dealing with an equation that only involves addition and subtraction ...you can solve it juat as it is witout using any special method same applied to equations tht involve only multiplication and division ... because they are an (inverse) of each other... hope it helps

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Abi invests £500 for 4 years in a bank account.
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7 0
3 years ago
Audrey, an astronomer is searching for extra-solar planets using the technique of relativistic lensing. Though there are believe
Stolb23 [73]

Answer:

Step-by-step explanation:

The model N (t), the number of planets found up to time t, as a Poisson process. So, the N (t) has distribution of Poison distribution with parameter (\lambda t)

a)

The mean for a month is, \lambda = \frac{1}{3} per month

E[N(t)]= \lambda t\\\\=\frac{1}{3}(24)\\\\=8

(Here. t = 24)

For Poisson process mean and variance are same,

Var[N (t)]= Var[N(24)]\\= E [N (24)]\\=8

 

(Poisson distribution mean and variance equal)

 

The standard deviation of the number of planets is,

\sigma( 24 )] =\sqrt{Var[ N(24)]}=\sqrt{8}= 2.828

b)

For the Poisson process the intervals between events(finding a new planet) have  independent  exponential  distribution with parameter \lambda. The  sum  of K of these  independent exponential has distribution Gamma (K, \lambda).

From the given information, k = 6 and \lambda =\frac{1}{3}

Calculate the expected value.

E(x)=\frac{\alpha}{\beta}\\\\=\frac{K}{\lambda}\\\\=\frac{6}{\frac{1}{3}}\\\\=18

(Here, \alpha =k and \beta=\lambda)                                                                      

C)

Calculate the probability that she will become eligible for the prize within one year.

Here, 1 year is equal to 12 months.

P(X ≤ 12) = (1/Г  (k)λ^k)(x)^(k-1).(e)^(-x/λ)

=\frac{1}{Г  (6)(\frac{1}{3})^6}(12)^{6-1}e^{-36}\\\\=0.2148696\\=0.2419\\=21.49%

Hence, the required probability is 0.2149 or 21.49%

5 0
3 years ago
Complete the following statement. A fraction in lowest terms is in its __________________________________
pantera1 [17]

Answer:

Reduced form

Step-by-step explanation:

Hope this helps!

7 0
3 years ago
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