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3 years ago

Complete the following statement. A fraction in lowest terms is in its __________________________________

Mathematics

1 answer:

pantera1 [17]3 years ago

7 0

Answer:

Reduced form

Step-by-step explanation:

Hope this helps!

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What type of health screening would this patient most likely receive?

ivolga24 [154]

Answer:

she would need annual breast cancer screening with mammograms.

Step-by-step explanation:

hope this helps! hope you have a nice day.

8 0

3 years ago

Simplify the expression 4(2x - 3y) ASAP

uranmaximum [27]

Answer:

8x - 12y

Step-by-step explanation:

4(2x-3y)

Distribute/multiply the 4 to everything in the parentheses

4 * 2x = 8x 4 * -3y = -12y

8x - 12y

4 0

3 years ago

Read 2 more answers

In 2003 there were 1078 JC Penney stores and in 2007 there were 1067 stores.

Tamiku [17]

Answer:

a) $f(s)=\frac{-11}{3}s+\frac{3245}{3}$ $f(1)=1078 stores$ b) 2012, 1049 stores. 2014, 1041 stores. c) Yes it is a downsizing company.

Step-by-step explanation:

s=year | f(s) = number of stores per year

1 | 1078

4| 1067

$m=\frac{1067-1078}{4-1}\Rightarrow m=\frac{-11}{3}\\1078=-\frac{11}{3}*1+b\Rightarrow b=\frac{3245}{3}\\f(s)=\frac{-11}{3}s+\frac{3245}{3}$

s=1 in 2003

$s=1 year =2003\\ Testing\\f(1)=\frac{-11}{3}(1)+\frac{3245}{3}=\frac{3234}{3}=1078\\ f(1)=1078$

b) For 2012, s=9. For 2014, s=11

$\\f(s)=\frac{-11}{3}s+\frac{3245}{3}\\ \\f(9)=\frac{-11}{3}(9)+\frac{3245}{3}\cong1049\\\\f(11)=\frac{-11}{3}(11)+\frac{3245}{3}\cong=1041$

c) In deed. Since the function shows a decreasing amount of JC Penney stores. Maybe this is a downsizing from this company, progressively closing some stores.

4 0

3 years ago

Suppose that contamination particle size (in micrometers) canbe modeled as

asambeis [7]

Answer:

c) 2

d) 0.96

Step-by-step explanation:

We are given the following in the question:

$f(x) = 2x^{-3}, x > 1\\~~~~~~~= 0, x \leq 1$

a) probability density function.

$\displaystyle\int^{\infty}_{\infty}f(x) dx = 1\\\\\displaystyle\int^{\infty}_{-\infty}2x^{-3}dx = 1\\\\\displaystyle\int^{\infty}_{1}2x^{-3}dx\\\\\Rightarrow \big[-x^{-2}\big]^{\infty}_1\\\\\Rightarrow -(0-1) = 1$