Answer:
88 cm³
Step-by-step explanation:
![V=\frac{lwh}{3}](https://tex.z-dn.net/?f=V%3D%5Cfrac%7Blwh%7D%7B3%7D)
V = (11 × 4 × 6) ÷ 3
88 cm³
Answer:
x > -5.25
Step-by-step explanation:
![\frac{dr}{dt} = 6.79 \: \frac{m}{s}](https://tex.z-dn.net/?f=%20%5Cfrac%7Bdr%7D%7Bdt%7D%20%20%3D%206.79%20%5C%3A%20%20%5Cfrac%7Bm%7D%7Bs%7D%20)
Step by Step Explanation:
The area a is defined as
![a = \pi {r}^{2}](https://tex.z-dn.net/?f=a%20%3D%20%5Cpi%20%20%20%7Br%7D%5E%7B2%7D%20)
Now take derivative of the above expression with respect to time:
![\frac{da}{dt} = 2\pi r \frac{dr}{dt}](https://tex.z-dn.net/?f=%20%5Cfrac%7Bda%7D%7Bdt%7D%20%20%3D%202%5Cpi%20r%20%5Cfrac%7Bdr%7D%7Bdt%7D%20)
Solving for dr/dt, we then get
![\frac{dr}{dt} = \frac{1}{2\pi r} \frac{da}{dt}](https://tex.z-dn.net/?f=%20%5Cfrac%7Bdr%7D%7Bdt%7D%20%20%3D%20%20%5Cfrac%7B1%7D%7B2%5Cpi%20r%7D%20%20%5Cfrac%7Bda%7D%7Bdt%7D%20)
Note that da/dt = 900 m^2/s and when the area of the oil slick is 1400 m^2, the radius r is r = √(1400/π) = 21.1 m. Therefore,the rate at which the radius is increasing dr/dt is
![\frac{dr}{dt} = \frac{1}{2\pi(21.1 \: m)}(900 \frac{ {m}^{2} }{s} ) = 6.79 \frac{m}{s}](https://tex.z-dn.net/?f=%20%5Cfrac%7Bdr%7D%7Bdt%7D%20%20%3D%20%20%5Cfrac%7B1%7D%7B2%5Cpi%2821.1%20%5C%3A%20m%29%7D%28900%20%20%5Cfrac%7B%20%7Bm%7D%5E%7B2%7D%20%7D%7Bs%7D%20%29%20%3D%206.79%20%5Cfrac%7Bm%7D%7Bs%7D%20)
just multiply 45 time 31!
Answer:
p = 2 or p = - 18
Step-by-step explanation:
given
= 5 ( multiply both sides by 2 )
| p + 8 | = 10
The expression inside the absolute value can be positive or negative
that is p + 8 = ± 10
p + 8 = 10 ⇒ p = 10 - 8 = 2
p + 8 = - 10 ⇒ p = - 10 - 8 = - 18