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Whitepunk [10]
3 years ago
10

Sdsdsdsdsdssdsdsdsdsds

Mathematics
1 answer:
I am Lyosha [343]3 years ago
8 0
*ahem* ..... yODeL-a-heE yoDEL-A-HoO
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The daily maximum temperatures, in degrees Fahrenheit, for Greenville is recorded for one week in the summer.
aliya0001 [1]

Answer:

I dont know sorry

Step-by-step explanation:

3 0
3 years ago
Which of the following matrices is the solution matrix for the given system of equations? x + 5y = 11 x - y = 5
givi [52]
<h2>The required solution is x = 6 and y = 11 </h2>

Step-by-step explanation:

Given system of equations are

x+5y = 11 and x-y =5

A= \left[\begin{array}{cc}1&5\\1&-1\end{array}\right]                            X=\left[\begin{array}{c}x\\y\end{array}\right]

and          B= \left[\begin{array}{c}11\\5\end{array}\right]

∴AX=B

adj A = \left[\begin{array}{cc}{-1}&{-5}\\{-1}&1\end{array}\right]

A= \left|\begin{array}{cc}1&5\\1&-1\end{array}\right|=-6

∴A^{-1} =\frac{adj A}{|A|}

So,A^{-1} =\frac{ \left[\begin{array}{cc}{-1}&{-5}\\{-1}&1\end{array}\right]}{-6}

A^{-1} ={ \left[\begin{array}{c \c}  {{\frac{1}{6} }}&{\frac{5}{6}}\ \\  {{\frac{1}{6} }}&{\frac{-1}{6}} \end{array}\right]}

X =A^{-1}\times B

⇒\left[\begin{array}{c}x\\y\end{array}\right] ={ \left[\begin{array}{c \c}  {{\frac{1}{6} }}&{\frac{5}{6}}\ \\  {{\frac{1}{6} }}&{\frac{-1}{6}} \end{array}\right]} \times \left[\begin{array}{c}11\\5\end{array}\right]

⇒\left[\begin{array}{c}x\\y\end{array}\right] ={ \left[\begin{array}{c}  {6}\\  {11} \end{array}\right]}

∴ x= 6 and y = 11

The required solution is x = 6 and y = 11

7 0
3 years ago
The image is below (I MARK BRAINLIEST)
Sedaia [141]

Answer:

option a

Step-by-step explanation:

7 0
3 years ago
What is this number in standard form?
balandron [24]

Answer: y=5(x+15)2−26 5

8 0
3 years ago
Submarine a is position at -1100 feet in relation to sea level. Submarine be is position at -800 feet in relation to sea level.
Natasha_Volkova [10]

Answer:

<u>Submarine A needs to travel at 30 feet per minute and the Submarine B at a lower speed, 20 feet per minute. </u>

Step-by-step explanation:

This is the information given to solve the question:

Submarine A position = - 1,100 feet

Submarine B position = - 800 feet

New position for Submarine A and B = - 200 feet

Duration of the travel = 30 minutes

Distance that Submarine A need to travel = - 200 + 1,100 = 900 feet

Distance that Submarine B need to travel = - 200 + 800 = 600 feet

For calculating the speed, we do this new calculation:

Speed Submarine A = Distance that Submarine A need to travel/Duration of the travel

Speed Submarine A = 900 feet/30 minutes

Speed Submarine A = 30 feet/minute (Dividing by 30)

Speed Submarine B = 600 feet/30 minutes

Speed Submarine B = 20 feet/minute (Dividing by 30)

<u>Submarine A needs to travel at 30 feet per minute and the Submarine B at a lower speed, 20 feet per minute. </u>

7 0
3 years ago
Read 2 more answers
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