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VARVARA [1.3K]
2 years ago
8

If you roll two fair six-sided dice what is the probability that the sum is:

Mathematics
1 answer:
blsea [12.9K]2 years ago
6 0

Answer: If you roll two fair six-sided dice, the probability that the sum is 5 or lower is 5/18.

Explanation: Probability can be defined as the ratio of the number of favorable outcomes to the total number of outcomes of an event.

For an experiment having n number of outcomes, the number of favorable outcomes can be denoted by x

Let ‘x’ be the number on the first dice.

‘Y’ be the number on second dice.

We have to find the probability that the sum is 5 or lower i.e. (x + y) <= 5.

Total number of possible results from two six-sided dice is 6 × 6 = 36.

The possible results that the sum is lower than 4 is (1,1), (1,2), (1,3), (1,4), (2,1), (2,2), (2,3), (3,1), (3,2) and (4,1).

Number of possible results for the sum is 5 or lower is 10.

The probability that the sum is 5 or lower = 10/36

=5/18

Therefore, the probability that the sum is 5 or lower is 5/18.

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dem82 [27]

Answer:

p = -3.5

Step-by-step explanation:

Simplifying

9 + -4(2p + -1) = 41

Reorder the terms:

9 + -4(-1 + 2p) = 41

9 + (-1 * -4 + 2p * -4) = 41

9 + (4 + -8p) = 41

Combine like terms: 9 + 4 = 13

13 + -8p = 41

Solving

13 + -8p = 41

Solving for variable 'p'.

Move all terms containing p to the left, all other terms to the right.

Add '-13' to each side of the equation.

13 + -13 + -8p = 41 + -13

Combine like terms: 13 + -13 = 0

0 + -8p = 41 + -13

-8p = 41 + -13

Combine like terms: 41 + -13 = 28

-8p = 28

Divide each side by '-8'.

p = -3.5

Simplifying

p = -3.5

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1 year ago
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A study of consumer smoking habits includes A people in the 18-22 age bracket (B of whom smoke), C people in the 23-30 age brack
madreJ [45]

The correct question is:

A study of consumer smoking habits includes 167 people in the 18-22 age bracket (59 of whom smoke), 148 people in the 23-30 age bracket (31 of whom smoke), and 85 people in the 31-40 age bracket (23 of whom smoke). If one person is randomly selected from this sample, find the probability of getting someone who is age 23-30 or smokes

Answer:

The probability of getting someone who is age 23-30 or smokes = 0.575

Step-by-step explanation:

We are given;

Number consumers of age 18 - 22 = 167

Number of consumers of ages 22 - 30 = 148

Number of consumers of ages 31 - 40 = 85

Thus,total number of consumers in the survey = 167 + 148 + 85 = 400

We are also given;

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Number of consumers of ages 22 - 30 who smoke = 31

Number of consumers of ages 31 - 40 who smoke = 23

Total number of people who smoke = 59 + 31 + 23 = 113

Let event A = someone of age 23-30 and event B = someone who smokes. Thus;

P(A) = 148/400

P(B) = 113/400

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Now, from addition rule in sets which is given by;

P(A or B) = P (A) + P (B) – P (A and B)

We can now solve the question.

Thus;

P(A or B) = (148/400) + (113/400) - (31/400)

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Since we want just the top 20% applicants and the data is normally distributed, we can use a z-score table to check the z-score that gives this percentage.

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We want a z* such that:

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But, to use a value that is in a z-score table, we do the following:

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So, we want a z-score that give a percentage of 80% for the value below it.

Using the z-score table or a z-score calculator, we can see that:

\begin{gathered} P(zNow that we have the z-score cutoff, we can convert it to the score cutoff by using:[tex]z=\frac{x-\mu}{\sigma}\Longrightarrow x=z\sigma+\mu

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Answer:

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Multiply the equation by 3

3y = -x + 21

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3 years ago
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