Answer:
Encrypt this binary string into ciphertext: 110000. Include
in your answer the formula the decoder would use to decrypt your cipher text in the format (coded answer) x N mod (m) = Y
-Decrypt this ciphertext into a binary string: 106
Now that you can see how public and private keys work in a real-world scenario, please explains how it works for computers and internet communications in relation to cybersecurity.
Explanation: ……………..
Answer:
1. Export
2. Create PDF/XPS document
3. Standard
4. Click Publish
Explanation:
I got wrong on edg and found the correct answer
public class JavaApplication82 {
public static void main(String[] args) {
for (int i = 1; i <= 9; i++){
for (int w = 0; w < i; w++){
System.out.print("*");
}
System.out.println("");
}
}
}
This works for me.
<span>Assuming that the language is C++ and that the following variables exist:
bonusscores is an array of some numeric type (float, double, int, etc).
nent is an integer indicating how many elements are in bonusscores.
Also assuming that the array is 0 based, so legal subscripts range from 0 to nent-1.
// Code starts here
for(int x = 0; x < (nent-1); ++x) {
bonusscores[x] = bonusscores[x] + bonusscores[x+1];
}
// Code ends here
Thing to note, since the last element isn't modified, the range for the for loop is reduced by 1 so that every element to actually be modified is visited, but the last element isn't. And since each element after modification isn't needed for future modifications, it's safe to change them in situ.</span>
