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IgorC [24]
3 years ago
12

____________________deals with syntax and semantics ofinformation exchange.

Computers and Technology
1 answer:
Goshia [24]3 years ago
3 0

Answer:

The answer is (a).Presentation Layer

Explanation:

This layer is located at the 6th level of the OSI model, responsible for delivering and formatting the information to the upper layer for further processing. This service is needed because different types of computer uses different data representation. The presentation layer handles issues related to data presentation and transport, including encryption,translation and compression.

You might be interested in
Which pdu is processed when a host computer is de-encapsulating a message at the transport layer of the tcp/ip model?.
yulyashka [42]

The PDU that is processed when a host computer is de-encapsulating a message at the transport layer of the tcp/ip model is segment.

<h3>What is this PDU about?</h3>

Note that in the transport layer, a host computer is said to often de-encapsulate  what we call a segment so that they can be able to put back data to an acceptable or given format through the use of the application layer protocol that belongs to the TCP/IP model.

Therefore, The PDU that is processed when a host computer is de-encapsulating a message at the transport layer of the tcp/ip model is segment as it is the right thing to do.

Learn more about host computer from

brainly.com/question/553980

5 0
2 years ago
We may think of relationships in the E/R model as having keys, just as entity sets do. Let R be a relationship among the entity
BaLLatris [955]

Explanation:

1

R is many - many;

in this case we have that E1 is not what should be used to determine E2 and in this same way, W2 is not what should determine E1. So non of these can be a key on its own.

2.

R is many-one from E1 to E2

in this case there are 2 tuples (f1,f2) and (e1,e2) which have to be the same if they have the same key attribute for E1. All of them are the same so all the pairs are the same.

3.

R is many-one from E2 to E1:

the explanation for this is is almost the same with that of b. we apply the same logic. since for all keys, all pairs and sets are the same.

4.

R is one-one:

E1 is what determines E2 and likewise, E2 is what determines E1. irrespective of the key that is used, key K is going to the same value of n.

8 0
4 years ago
A _ operating system is usually used in personal computers
Eddi Din [679]
A windows operating system.
Or linux/Mac.
4 0
3 years ago
1. Write a toString method for this class. The method should return a string containing the radius and area of the circle.
Lady bird [3.3K]

Answer:

public class Circle {

private double radius;

public Circle(double r)

{

radius = r;

}

public double getArea()

{

return Math.PI * radius * radius;

}

public double getRadius()

{

return radius;

}

public String toString()

{

String str;

str = "Radius: " + radius +

"Area: " + getArea();

return str;

}

public boolean equals(Circle c)

{

boolean status;

if(c.getRadius() == radius)

status = true;

else

status = false;

return status;

}

public boolean greaterThan(Circle c)

{

boolean status;

if(c.getArea() > getArea())

status = true;

else

status = false;

return status;

}

}

Explanation:

There is nothing with the logic of your code it work fine the problem is with the structure of your code you added an extra  curly brace before declaring (r)

****************************** Am talking about this section **********************

public class Circle {

{

private double radius;

****************************   It should be    *******************************************

public class Circle {

private double radius;

6 0
3 years ago
Consider the following code:
pishuonlain [190]

In python the % operator is modulo. Modulo returns the remainder of two numbers.

19 % 5 = 4 therefore,

print(x%y) would output 4

7 0
3 years ago
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