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IgorC [24]
3 years ago
12

____________________deals with syntax and semantics ofinformation exchange.

Computers and Technology
1 answer:
Goshia [24]3 years ago
3 0

Answer:

The answer is (a).Presentation Layer

Explanation:

This layer is located at the 6th level of the OSI model, responsible for delivering and formatting the information to the upper layer for further processing. This service is needed because different types of computer uses different data representation. The presentation layer handles issues related to data presentation and transport, including encryption,translation and compression.

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Answer:

Earthquake

Explanation:

Around 3 million people were affected by this disaster and it was the most devastating natural disaster ever experienced in Haiti. Roughly 250,000 lives were lost and 300,000 people were injured.

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What is an border in html
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Look at the logic program below. Set a breakpoint after each commented instruction. You can also single step through the program
Goshia [24]

Using programming knowledge, it is possible to use programming logic, we can differentiate and find the terms

<h3>Writing the code and understanding the programming logic:</h3>

<em>.data</em>

<em>sourceword:</em>

<em>.word 0xAB</em>

<em>wordmask:</em>

<em>.word 0xCF</em>

<em>operand:</em>

<em>.long 0xAA</em>

<em>.text</em>

<em>.globl _start</em>

<em>_start:</em>

<em>movw sourceword, %ax # ax=0x00AB ( move the word value of sourceword =0x00AB to ax register.)</em>

<em>movw %ax, %bx # bx=0x00AB ( copy the value of ax to bx register.)</em>

<em>xorw %cx, %cx # cx=0000 ( cx=cx XOR cx, that is clear cx register.)</em>

<em />

<em>andw wordmask, %ax # ax=0x008B ( ax=ax AND wordmask= 0x00AB AND 0x00CF= 0x008B)</em>

<em>orw wordmask, %bx # bx=0x00EF (bx=bx OR wordmask= 0x00AB OR 0x00CF= 0x00EF.)</em>

<em>xorw wordmask, %cx # cx=0x00CF (cx=cx XOR wordmask= 0x0000 XOR 0x00CF=0x00CF.)</em>

<em />

<em>movl operand, %eax # eax=0x000000AA. ( copy the 32-bit value of operand=0x000000AA to eax.)</em>

<em>movl %eax, %ebx # ebx=0x000000AA.( copy the value of eax to ebx.)</em>

<em>movl %eax, %ecx # ecx=0x000000AA. ( copy the value of eax to ecx.)</em>

<em />

<em>shll $3,%eax # eax=0x00000550. ( logical shift left of eax=0x000000AA by 3 bits.)</em>

<em />

<em># 0x000000AA=00000000000000000000000010101010</em>

<em />

<em># =>00000000000000000000010101010000=0x00000550.</em>

<em />

<em>rorl $4,%ebx # ebx=0xA000000A. (Rotate right ebx=0x000000AA by 4 bits.)</em>

<em />

<em># 0x000000AA=00000000000000000000000010101010</em>

<em />

<em>3 =>10100000000000000000000000001010= 0xA000000A.</em>

<em />

<em>sarl %ecx # here the count value to shift the bits not mentioned.</em>

<em />

<em># It is the arithmetic shift right instruction. the shifted left bits filled with MSB bit.</em>

See more about logic program at brainly.com/question/14970713

#SPJ1

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Answer:

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Building kitchen cabinets.

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