We are given with
dimensions of wheelbarrow = 2ft x 3ft x 1.5 ft
dimensions of truck = 11 ft x 8 ft x 6 ft
The volume of the wheelbarrow is 2(3)(1.5) = 9 ft3
The volume of the truck is 11(8)(6) = 528 ft3
70% of this is
528 ft3 (0.7) = 369.6 ft3
Dividing this by the volume of the wheelbarrow
369.6 ft3 / 9 ft3 = 41.07
He would need to use the wheelbarrow 42 times.
Answer:
The amount of punch mix to use is 3/4 gallons
Step-by-step explanation:
Let
x ----> parts of water
y ---> parts of punch mix
we know that
----> equation A
That means ---> The parts of water is 8 times the parts of punch mix
If we have 6 gal of water
then
substitute in the equation A
solve for y
Simplify
therefore
The amount of punch mix to use is 3/4 gallons
Answer:
im so sorry i answord but i need to get my frie.nd back. sorry
You would substitute 0.8 in for y and to get the equation 4x+8(0.8)=40. Then, you would simplify and get 4x+6.4=40. Next you would isolate x by subtracting 6.4 from both sides and get the equation 4x=33.6 and then you would divide both sides by 4 to get x=8.4.
The answer is : x=8.4
