Irrational................................
Answer:
4(3n+2) or 12n+8
Step-by-step explanation:
Given expression is:

The numerator of the fraction will be multiplied with 9n^2- 4
So, Multiplication will give us:

We can simplify the expression before multiplication.
The numerator will be broken down using the formula:
![a^2 - b^2 = (a+b)(a-b)\\So,\\= \frac{8[(3n)^2 - (2)^2]}{6n-4}\\ = \frac{8(3n-2)(3n+2)}{6n-4}](https://tex.z-dn.net/?f=a%5E2%20-%20b%5E2%20%3D%20%28a%2Bb%29%28a-b%29%5C%5CSo%2C%5C%5C%3D%20%5Cfrac%7B8%5B%283n%29%5E2%20-%20%282%29%5E2%5D%7D%7B6n-4%7D%5C%5C%20%3D%20%5Cfrac%7B8%283n-2%29%283n%2B2%29%7D%7B6n-4%7D)
We can take 2 as common factor from denominator

Hence the product is 4(3n+2) or 12n+8 ..
Answer:
(a) See attachment for tree diagram
(b) 24 possible outcomes
Step-by-step explanation:
Given


Solving (a): A possibility tree
If urn 1 is selected, the following selection exists:
![B_1 \to [R_1, R_2, R_3]; R_1 \to [B_1, R_2, R_3]; R_2 \to [B_1, R_1, R_3]; R_3 \to [B_1, R_1, R_2]](https://tex.z-dn.net/?f=B_1%20%5Cto%20%5BR_1%2C%20R_2%2C%20R_3%5D%3B%20R_1%20%5Cto%20%5BB_1%2C%20R_2%2C%20R_3%5D%3B%20R_2%20%5Cto%20%5BB_1%2C%20R_1%2C%20R_3%5D%3B%20R_3%20%5Cto%20%5BB_1%2C%20R_1%2C%20R_2%5D)
If urn 2 is selected, the following selection exists:
![B_2 \to [B_3, R_4, R_5]; B_3 \to [B_2, R_4, R_5]; R_4 \to [B_2, B_3, R_5]; R_5 \to [B_2, B_3, R_4]](https://tex.z-dn.net/?f=B_2%20%5Cto%20%5BB_3%2C%20R_4%2C%20R_5%5D%3B%20B_3%20%5Cto%20%5BB_2%2C%20R_4%2C%20R_5%5D%3B%20R_4%20%5Cto%20%5BB_2%2C%20B_3%2C%20R_5%5D%3B%20R_5%20%5Cto%20%5BB_2%2C%20B_3%2C%20R_4%5D)
<em>See attachment for possibility tree</em>
Solving (b): The total number of outcome
<u>For urn 1</u>
There are 4 balls in urn 1

Each of the balls has 3 subsets. i.e.
![B_1 \to [R_1, R_2, R_3]; R_1 \to [B_1, R_2, R_3]; R_2 \to [B_1, R_1, R_3]; R_3 \to [B_1, R_1, R_2]](https://tex.z-dn.net/?f=B_1%20%5Cto%20%5BR_1%2C%20R_2%2C%20R_3%5D%3B%20R_1%20%5Cto%20%5BB_1%2C%20R_2%2C%20R_3%5D%3B%20R_2%20%5Cto%20%5BB_1%2C%20R_1%2C%20R_3%5D%3B%20R_3%20%5Cto%20%5BB_1%2C%20R_1%2C%20R_2%5D)
So, the selection is:


<u>For urn 2</u>
There are 4 balls in urn 2

Each of the balls has 3 subsets. i.e.
![B_2 \to [B_3, R_4, R_5]; B_3 \to [B_2, R_4, R_5]; R_4 \to [B_2, B_3, R_5]; R_5 \to [B_2, B_3, R_4]](https://tex.z-dn.net/?f=B_2%20%5Cto%20%5BB_3%2C%20R_4%2C%20R_5%5D%3B%20B_3%20%5Cto%20%5BB_2%2C%20R_4%2C%20R_5%5D%3B%20R_4%20%5Cto%20%5BB_2%2C%20B_3%2C%20R_5%5D%3B%20R_5%20%5Cto%20%5BB_2%2C%20B_3%2C%20R_4%5D)
So, the selection is:


Total number of outcomes is:



Answer:
The answer would be 3/16
Step-by-step explanation:
Total no.of beads = 16
No.of blue beads = 3
Probability of picking a blue bead = 3/16
Answer:
The calculated t-value is t=0.47.
Step-by-step explanation:
<em>The question is incomplete:</em>
<em>"Americans typically eat quickly and do not spend time enjoying their meal. A researcher plans to test if those trained in mindfulness will take more time to enjoy their meal (that is, they will spend more time eating than the general population). The general population spends an average of 68 minutes per day combined eating their three meals. The researcher trains a sample of 16 individuals in mindfulness and then collects data on how long they spend eating per day. The sample mean for those trained in mindfulness equals 74; the SS = 150. What is the calculated t-value? Round your answer to two decimal places."</em>
The degrees of freedom are (n-1)=(16-1)=15
The standard deviation is:

The t-value can be calculated as:
