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liberstina [14]
4 years ago
6

The number of hours, t, that bacteria spread 10-fold can be modeled by the equation B(t) = B0(10)2t. There are 15 bacteria prese

nt initially and a biologist wishes to find out how many hours will elapse until there are 1,845 bacteria present. What is the exact value for the number of hours elapsed, t, in the equation 1,845 = 15(10)2t?
Mathematics
1 answer:
Whitepunk [10]4 years ago
4 0
W is your awnser. just w


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-6c&lt; -12<br> what will the answear be
murzikaleks [220]

Answer:c>2

Step-by-step explanation:

-6c (divide) (-6) > -12 (divide) (-6)

c>-12 (divide) (-6)

c>12 (divide) 6

c> 2

8 0
3 years ago
Among two supplementary angles, the measure of the larger angle is 44°
zhuklara [117]

Answer:

68° and 112°

Step-by-step explanation:

Supplementary angles sum to 180°

let the smaller angle be x then the larger angle is x + 44 , then

x + x + 44 = 180 , that is

2x + 44 = 180 ( subtract 44 from both sides )

2x = 136 ( divide both sides by 2 )

x = 68

Smaller angle = 68° and

larger angle = x + 44 = 68 + 44 = 112°

6 0
3 years ago
PLEASE HELP/ANSWER! From 1980 to 1990, Lior’s weight increased by 25%. If his weight was k kilograms in 1990, what was it in 198
Elena-2011 [213]

The weight in 1980 is \frac{4k}{5} kilograms

<em><u>Solution:</u></em>

From 1980 to 1990, Lior’s weight increased by 25%

His weight is "k" kilograms in 1990

<em><u>To find: weight in 1980</u></em>

This is a percentage increase problem

Let "x" be the weight in kilograms in 1980

<em><u>The percentage increase is given by formula:</u></em>

\text{Percentage increase } = \frac{\text{Final value - initial value}}{\text{initial value}} \times 100

Here,

Initial value in 1980 = x

Final value in 1990 = k

Percentage increase = 25 %

<em><u>Substituting the values in formula,</u></em>

25 = \frac{k-x}{x} \times 100\\\\25x = 100(k-x)\\\\x = 4(k-x)\\\\x = 4k - 4x\\\\5x = 4k\\\\x = \frac{4k}{5}

Thus the weight in kilograms in 1980 is \frac{4k}{5}

7 0
4 years ago
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luda_lava [24]

We want to find the value of the 8 in 281,480,100

Let's find the place value of each of the numbers:

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1 - millions

4 - hundred thousands

8 - ten thousands

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1 - hundreds

0 - tens

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I see there are two 8's so I wouldn't be too sure of which value to find, but just in case, we have the chart made above for place values.

There is one 8 at the ten millions value.

There is one 8 at the ten thousands value.

7 0
3 years ago
Read 2 more answers
100 divided by 235 ?
Alina [70]

Answer:

100 divided by 235=0.425

6 0
3 years ago
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