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tensa zangetsu [6.8K]
4 years ago
15

Find the standard form of the equation of the parabola with a focus at (0, 4) and a directrix at y = -4. Answer choices: y = 1/1

6x2 y2 = 16x y2 = 4x y = 1/4x2
Mathematics
1 answer:
ozzi4 years ago
3 0

Answer:

a) The standard form of the equation

y=\frac{16}{x^{2} }

Step-by-step explanation:

<u><em>Explanation:-</em></u>

    A parabola is the set of all points in a plane that are equidistant from a fixed line and a fixed point (not in a line) in the plane

• The Fixed line is called the directrix of the parabola.

• The Fixed point is called the focus of the parabola.

• <em>A line through the focus and perpendicular to the directrix is called the axis of the parabola. </em>

• The point of intersection of parabola with the axis is called the vertex of the parabola.

<em>Given Focus of the parabola S(0,a)= (0,4)</em>

<em>Given Focus is lies on y-axis and the directrix is parallel to x-axis</em>

<em>Given directrix of the parabola y = -4</em>

<em>Directrix     y = -a </em>

<em>           </em>

<em>Standard form of the parabola </em>

<em>                                 x² = 4ay</em>

<em>                                x² = 4(4)y</em>

<em>                               x² = 16y</em>

<em>                               </em>y=\frac{16}{x^{2} }<em />

<em />

                               

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