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8 months ago

dog brought a new jet ski for $299 down in 14 monthly payments are $57 how much did Doug pay for the jet ski total

Mathematics

1 answer:

Effectus [21]8 months ago

8 0

If he paid $57 monthly for 14 months, the total amount paid is:

$57\times14=798$

He paid $798 in total

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A factory used 3/4 of a barrel of almonds to make 3 batches of granola bars. How many barrels of almonds did the factory put in

Lelu [443]

Answer:

1/4 barrels of almonds

Step-by-step explanation:

(3/4)/3=(3/4)(1/3)=3/12=1/4

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3 years ago

Use the calculator to find the value of x for the equation: × + 3.2=6.3

Harman [31]

Answer:

x = 3.1

Step-by-step explanation:

Subtract 6.3 - 3.2 to find the value of x. You get 3.1.

Hope it helps!

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2 years ago

Read 2 more answers

I really need help on this please!!

Aleonysh [2.5K]

Solve for h
V = lwh

Divide lw on both sides, and you get
V / (lw) = h

Answer: b

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2 years ago

Two automobiles left simultaneously from cities A and B heading towards each other and met in 5 hours. The speed of the automobi

quester [9]

Answer:

450 km

Step-by-step explanation:

Equations

We can define 3 variables: a, b, d. Let "a" and "b" represent the speeds of the cars leaving cities A and B, respectively. Let "d" represent the distance between the two cities. We can write three equations in these three variables:

1. The relation between "a" and "b":

a = b -10 . . . . . . . the speed of car A is 10 kph less than that of car B

2. The relation between speed and distance when the cars leave at the same time:

d = (a +b)·5 . . . . . . distance = speed × time

3. Note that the time it takes car B to travel 150 km to the meeting point is (150/b). (time = distance/speed) The total distance covered is ...

distance covered by car A in 4 1/2 hours + distance covered by both cars (after car B leaves) = total distance

4.5a + (150/b)(a +b) = d

Solution

Substituting for d, we have ...

4.5a + 150/b(a +b) = 5(a +b)

4.5ab +150a +150b = 5ab +5b^2 . . . . . . multiply by b, eliminate parentheses

5b^2 +0.5ab -150(a +b) = 0 . . . . . . . . . . subtract the left side

Now, we can substitute for "a" and solve for b.

5b^2 + 0.5b(b-10) -150(b -10 +b) = 0

5.5b^2 -5b -300b +1500 = 0 . . . . . . . . eliminate parentheses

11b^2 -610b +3000 = 0 . . . . . . . . . . . . . multiply by 2

(11b -60)(b -50) = 0 . . . . . . . . . . . . . . . . factor

The solutions to this equation are ...

b = 60/11 = 5 5/11 . . . and . . . b = 50

Since b must be greater than 10, the first solution is extraneous, and the values of the variables are ...

b = 50
a = b-10 = 40
d = 5(a+b) = 5(90) = 450

The distance between A and B is 450 km.

_____

Check

When the cars leave at the same time, their speed of closure is the sum of their speeds. They will cover 450 km in ...

(450 km)/(40 km/h +50 km/h) = 450/90 h = 5 h

When car A leaves 4 1/2 hours early, it covers a distance of ...

(4.5 h)(40 km/h) = 180 km

before car B leaves. The distance remaining to be covered is ...

450 km - 180 km = 270 km

When car B leaves, the two cars are closing at (40 +50) km/h = 90 km/h, so will cover that 270 km in ...

(270 km)/(90 km/h) = 3 h

In that time, car B has traveled (3 h)(50 km/h) = 150 km away from city B, as required.

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3 years ago

Read 2 more answers

The sides of an equilateral triangle are increasing at a rate of 10 cm/min. at what rate is the area of the triangle increasing

Alinara [238K]

Area of a triangle is given by

$Area= \frac{1}{2} ab\sin C= \frac{1}{2} s^2\sin C$

Since the sides of an equilateral triangle are equal.

Differentiating the area of the triangle, we have:

$\frac{dA}{dt} = \frac{dA}{ds} \cdot \frac{ds}{dt} =(s\sin C) \frac{ds}{dt}$

where

$\frac{ds}{dt} =10\,cm/min \\ s=30 \, cm$

$\therefore \frac{dA}{dt} =(30\sin60)\times10=300\sin60=259.8\, cm^2/min$

Therefore, the rate is the area of the triangle increasing when the sides are 30 cm long is 259.8 cm^2 / min

8 0

3 years ago