Find the area of each shape and add.Let's start with the first semi-circle(half-circle)
If the area of a circle is πr² , then the area of a semi-circle is 1/2πr² where is 22/7 or 3.14, and r is the radius which is 1.8 meters
A=1/2πr²
A=1/2*22/7*1.8*1.8
A=5.09 m²(rounded to nearest hundredth)
Since the semi-circles are two and have the same radius, multiply the area of the first one by two or go through the same process again.
So 5.09 *2=10.18meters square is the area of the two semi-circles
Now, let's find the area of a rectangle which is length times width, where length is 6 meters and width is (1.8+1.8, because 1.8 is half the width)=3.6 meters
A=l*w
A=6*3.6
A=21.6meters square
Therefore the area of the shape is 10.18m²+21.6m²=219.888m²
Answer:
Total length after 33 days will be 117 miles
Step-by-step explanation:
A construction crew is lengthening a road. The road started with a length of 51 miles.
Average addition of the road is = 2 miles per day
Let the number of days crew has worked are D and length of the road is L, then length of the road can represented by the equation
L = 2D + 51
If the number of days worked by the crew is = 33 days
Then total length of the road will be L = 2×33 + 51
L = 66 + 51
L = 117 miles
Total length of the road after 33 days of the construction will be 117 miles.
When the domain of the function is continuous, a different approach may well be required, although even here we note that in practice, optimization problems are usually solved using a computer, so that in the final analysis the solutions are represented by strings of binary digits (bits).
