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3 years ago

Which statement is true

1 answer:

7 0

$\dfrac{3}{4} = \dfrac{3 \times 3}{4 \times 3} = \dfrac{9}{12}$

$\dfrac{4}{6} = \dfrac{4 \times 2}{6 \times 2} = \dfrac{8}{12}$

$\dfrac{9}{12} \ \textgreater \ \dfrac{8}{12}$

$\dfrac{3}{4} \ \textgreater \ \dfrac{4}{6}$

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There were 532 people at the Nutcracker. If admission was $24 for adults and $16 for children and $10,272 was collected, how man

anzhelika [568]

X = # adults

y = # children

system

24x+16y=$10272
x + y =532

4 0

3 years ago

15 total kids were at the park. 6 of them were girls. What % of the kids were girls?

Vikentia [17]

Answer:

40%

Step-by-step explanation:

6/15 = 0.4

0.4 * 100 = 40%

4 0

3 years ago

Read 2 more answers

Which of the following statements are not true in developing a confidence interval for the population mean?

frutty [35]

Answer:

b) The width of the confidence interval becomes narrower when the sample mean increases.

Step-by-step explanation:

The confidence interval can be calculated as:

$\bar{x} \pm \text{Test Statistic}\displaystyle\frac{\sigma}{\sqrt{n}}$

a) The width of the confidence interval becomes wider as the confidence level increases.

The above statement is true as the confidence level increases the width increases as the absolute value of test statistic increases.

b) The width of the confidence interval becomes narrower when the sample mean increases.

The above statement is false. As the sample mean increases the width of the confidence interval increases.

c) The width of the confidence interval becomes narrower when the sample size n increases.

The above statement is true as the sample size increases the standard error decreases and the confidence interval become narrower.

8 0

3 years ago

The coordinates of the endpoints of ST are (-2,3) and (3, y) respectively supposethe distance between s and t us 13 units.What v

igor_vitrenko [27]

Answer:

The values of y would be -9 and 15

Step-by-step explanation:

we know that

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

we have

$d=13\ units$

S(-2,3) and T(3,y)

substitute the given values in the formula and solve for y

$13=\sqrt{(y-3)^{2}+(3+2)^{2}}$

$13=\sqrt{(y-3)^{2}+25}$

squared both sides

$169=(y-3)^{2}+25$

$(y-3)^{2}=169-25$

$(y-3)^{2}=144$

take square root both sides

$y-3=(+/-)12$

$y=3(+/-)12$

$y=3(+)12=15$

$y=3(-)12=-9$

therefore

The values of y would be -9 and 15

5 0

3 years ago

Who in this list would NOT request a copy of your credit report?

mrs_skeptik [129]

Answer:

a grocery store

Step-by-step explanation:

it seems strange that most of those would request a report card at all

6 0

3 years ago