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gregori [183]
3 years ago
12

To pass a course with a C grade, a student must have an average of 70 or greater. A student's grades on three tests are 69, 77 a

nd 65 Find what score the student must get on the next test to get a C average or better
What grade must the student get?
Mathematics
2 answers:
Ivan3 years ago
6 0

Answer:

x=69

so he must have scored over 69

Step-by-step explanation:

Genrish500 [490]3 years ago
3 0

Answer:

Grade≥69(at least 69)

Step-by-step explanation:

(77+69+65+x)/4=70

x=69

so he must get 69 or more

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Who can help me needed for tomorrow please
blagie [28]

a) 170.00 =8n -30

200= 8n

n = 200/8 = 25 items


b) since the expenses increased the profits would decrease

profit = 8(25)-40 = 200-40 = 160

170-160 = 10.00

 profit decreased by $10.00

6 0
3 years ago
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Use the zero product property to find the solutions to the equation x^2-15x-100=0
Helen [10]

Answer:

It’s c

Step-by-step explanation:

5 0
2 years ago
A cafe sells puffs. 5/9 are beef and 1/3 are chicken. The remaining 18 are tuna. Calculate 1. What fraction of the puffs are tun
Ksivusya [100]
Let n be the total number of puffs. Now we can write:
n=\frac{5}{9}n+\frac{1}{3}n+18
Adding the fractional value of n, we get:
n=\frac{5+3}{9}n+18
Simplifying and rearranging gives us:
n-\frac{8}{9}n=18
Therefore we can simplify to get:
\frac{1}{9}n=18
and finally
n=18\times9=?
The fraction of the puff that are tuna is found from:
\frac{18}{18\times9}=\frac{1}{9}
7 0
3 years ago
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Write the relation as a set of ordered pairs.
AveGali [126]

Answer:

Is B (-2,-1),(0,0),(2,1)

Step-by-step explanation:

x y

-2 -1

0 0

2 1

I think!!??

5 0
3 years ago
Triangle A″B″C″ is formed by a reflection over x = 1 and dilation by a scale factor of 2 from the origin. Which equation shows t
andrew-mc [135]

Answer:

segment AB over segment A double prime B double prime = the square root of 13 over 2 times the square root of 13

Step-by-step explanation:

Triangle ABC has vertices at points A(-3,3), B(1,-3) and C(-3,-3).

1. Reflection over x = 1 maps vertices A, B and C as follows

  • A(-3,3)→A'(5,3);
  • B(1,-3)→B'(1,3);
  • C(-3,-3)→C'(5,-3).

2. Dilation by a scale factor of 2 from the origin has the rule

(x,y)→(2x,2y)

So,

  • A'(5,3)→A''(10,6);
  • B'(1,3)→B''(2,6);
  • C'(5,-3)→C''(10,-6)

See attached diagram for details

Note that

A''B''=2AB\\ \\A''C''=2AC\\ \\B''C''=2BC,\\ \\AB=\sqrt{(-3-1)^2+(3-(-3))^2}=\sqrt{16+36}=\sqrt{52}=2\sqrt{13}

so

\dfrac{AB}{A''B''}=\dfrac{2\sqrt{13}}{2\cdot 2\sqrt{13}}=\dfrac{\sqrt{13}}{2\sqrt{13}}

7 0
3 years ago
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