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gregori [183]
3 years ago
12

To pass a course with a C grade, a student must have an average of 70 or greater. A student's grades on three tests are 69, 77 a

nd 65 Find what score the student must get on the next test to get a C average or better
What grade must the student get?
Mathematics
2 answers:
Ivan3 years ago
6 0

Answer:

x=69

so he must have scored over 69

Step-by-step explanation:

Genrish500 [490]3 years ago
3 0

Answer:

Grade≥69(at least 69)

Step-by-step explanation:

(77+69+65+x)/4=70

x=69

so he must get 69 or more

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Hi what is the answer for a+5d+3x
sattari [20]
Well I tried doing it but depends what your trying to do with the equation but I got
x= -a/3 - 5d/3
3 0
3 years ago
In a G.P the difference between the 1st and 5th term is 150, and the difference between the
liubo4ka [24]

Answer:

Either \displaystyle \frac{-1522}{\sqrt{41}} (approximately -238) or \displaystyle \frac{1522}{\sqrt{41}} (approximately 238.)

Step-by-step explanation:

Let a denote the first term of this geometric series, and let r denote the common ratio of this geometric series.

The first five terms of this series would be:

  • a,
  • a\cdot r,
  • a \cdot r^2,
  • a \cdot r^3,
  • a \cdot r^4.

First equation:

a\, r^4 - a = 150.

Second equation:

a\, r^3 - a\, r = 48.

Rewrite and simplify the first equation.

\begin{aligned}& a\, r^4 - a \\ &= a\, \left(r^4 - 1\right)\\ &= a\, \left(r^2 - 1\right) \, \left(r^2 + 1\right) \end{aligned}.

Therefore, the first equation becomes:

a\, \left(r^2 - 1\right) \, \left(r^2 + 1\right) = 150..

Similarly, rewrite and simplify the second equation:

\begin{aligned}&a\, r^3 - a\, r\\ &= a\, \left( r^3 - r\right) \\ &= a\, r\, \left(r^2 - 1\right) \end{aligned}.

Therefore, the second equation becomes:

a\, r\, \left(r^2 - 1\right) = 48.

Take the quotient between these two equations:

\begin{aligned}\frac{a\, \left(r^2 - 1\right) \, \left(r^2 + 1\right)}{a\cdot r\, \left(r^2 - 1\right)} = \frac{150}{48}\end{aligned}.

Simplify and solve for r:

\displaystyle \frac{r^2+ 1}{r} = \frac{25}{8}.

8\, r^2 - 25\, r + 8 = 0.

Either \displaystyle r = \frac{25 - 3\, \sqrt{41}}{16} or \displaystyle r = \frac{25 + 3\, \sqrt{41}}{16}.

Assume that \displaystyle r = \frac{25 - 3\, \sqrt{41}}{16}. Substitute back to either of the two original equations to show that \displaystyle a = -\frac{497\, \sqrt{41}}{41} - 75.

Calculate the sum of the first five terms:

\begin{aligned} &a + a\cdot r + a\cdot r^2 + a\cdot r^3 + a \cdot r^4\\ &= -\frac{1522\sqrt{41}}{41} \approx -238\end{aligned}.

Similarly, assume that \displaystyle r = \frac{25 + 3\, \sqrt{41}}{16}. Substitute back to either of the two original equations to show that \displaystyle a = \frac{497\, \sqrt{41}}{41} - 75.

Calculate the sum of the first five terms:

\begin{aligned} &a + a\cdot r + a\cdot r^2 + a\cdot r^3 + a \cdot r^4\\ &= \frac{1522\sqrt{41}}{41} \approx 238\end{aligned}.

4 0
3 years ago
PLEASE HELP!
shusha [124]

<u>For -1:</u>

y = x + 6

y = 5

( -1, 5)

<u>For 0:</u>

y = x + 6

y = 6

(0, 6)

<u>For 2:</u>

y = x + 6

y = 8

(2,8)

<u>For 4:</u>

y = x + 6

y = 10

(4,10)

8 0
3 years ago
Central and inscribed angle practice
Gelneren [198K]

Answer:

sorry

Step-by-step explanation:

I don't know what you want , do you want to know how to construct an inscribed angle or what

3 0
3 years ago
Please help me with this answer having a hard time
Ipatiy [6.2K]

To solve this you must use the rules of PEMDAS (Parentheses, Exponent, Multiplication, Division, Addition, Subtraction)

In this problem we have double parentheses. Which one should we solve first? The answer to that is always the inner most ones:

13[ 6² ÷ (5² - 4²) + 9]

5² - 4²

^^^Here you will have to first take the square of both values

25 - 16

9

13[ 6² ÷ (9) + 9]

Now for the exponents

13[ 6² ÷ (9) + 9]

6²

36

13[ 36 ÷ 9 + 9]

Now for the division:

13[ 36 ÷ 9 + 9]

36 ÷ 9

4

13[ 4 + 9]

Now for the addition

13[ 4 + 9]

4 + 9

13

13[13]

Now for multiplication

169

Hope this helped!

~Just a girl in love with Shawn Mendes

5 0
3 years ago
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