The radius of the circle tangent to sides AC and BC and to the circumcircle of triangle ABC.
r= 24.
<h3>What is the radius of the circle tangent to sides AC and BC and to the circumcircle of triangle ABC.?</h3>
Generally, the equation for side lengths AB is mathematically given as
Triangle ABC has side lengths
Where
- AB = 65,
- BC = 33,
- AC = 56.
Hence
r √ 2 · (89 √ 2/2 − r √ 2) = r(89 − 2r),
r = 89 − 65
r= 24.
In conclusion, The radius of the circle tangent to sides AC and BC and to the circumcircle of triangle ABC.
r= 24.
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Answer:
Step-by-step explanation:
Answer: g = w² - 14w + 49
Step-by-step explanation:
Answer : option A
To find the range of scores that represents the middle 50 % of the student who took the test , we find inter quartile
Inter quartile range is the middle 50% of the given range of scores.
The difference between the upper quartile and lower quartile is the inter quartile that is middle 50%
From the diagram , we can see that
Upper quartile = 89
lower quartile = 65
So range is 65% to 89%
