Question

Find a numerical value of one trigonometric function of x if sinxcotx=1/3

Answer 1

Sin x cotx = sin x * cos x / sin x  = cos x

so cos x = 1/3

Answer 2

Answer:

A numerical value of one trigonometric function of x, for the given function would be $cos(x)=\frac{1}{3}$

Step-by-step explanation:

We know that there are many trigonometric functions, that can be expressed as functions of x, for example:

$sin(x)$

$cos(x)$

$tan(x)$

$cot(x)$

$csc(x)$

So, the problem is aking us for one trigonometric function of x, but gives us a product of functions of x, instead of one function of x. We note then, that

$cot(x)=\frac{cos(x)}{sin(x)}$

Therefore, we calculate from the given function

$sin(x)*\frac{cos(x)}{sin(x)}=cos(x)=\frac{1}{3}$

wich is our answer, furthermore, we could calculate the value of x for this case

$x=cos^-1(\frac{1}{3})\approx70.5$