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Yuliya22 [10]
4 years ago
15

Please help (photo attached below) ALGEBRA 1

Mathematics
1 answer:
frutty [35]4 years ago
3 0

Answer:

x =2

2 in, 6 in, 1 in

Step-by-step explanation:

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I will be including both an basic explanation of what it is and its proof.

I'm guessing you are either learning about conditional probability at school or preparing for competitions.

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P(A|B)=\frac{P(AintersectB)}{P(B)}

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Now we know that the probably that A and B both happens is the same as the probably that B and A both happens.

Therefore P(A|B) can be seen as P(B|A) multiplied by P(A) and then divided by P(B) which gives the right hand side of the first equation. And this is basically the theorem.

P(A|B)=\frac{P(B|A)P(A)}{P(B)}

**Note P(B) have to be not equal to 0 because having a 0 in the denominator would make this equation undefined.

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