Answer:
The numbers are -14,-13 and -12
Step-by-step explanation:
<u><em>The correct question is </em></u>
Find three consecutive integers such that the sum of the first, twice the second and three times the third is -76. What is the number?
Let
x ----> the first consecutive integer
x+1 ---> the second consecutive integer
x+2 ---> the third consecutive integer
we have that
solve for x
apply distributive property
Combine like terms
subtract 8 both sides
Divide by 6 both sides
so
therefore
The numbers are -14,-13 and -12
Answer:
Step-by-step explanation:
The given expression is 
We want to find the value of h(-9).
We substitute r=-9 to obtain:
We multiply out to obtain:
We simplify the denominator to obtain:
This is the same as:
Not sure if this is right or not, but I chose 125.11 after I typed in the equation, haven’t used R-value at all. Will comment if correct — APEX
Answer:
160 in^2
Step-by-step explanation:
Begin with cos(θ) = 5/13, θ in Quadrant IV
you should distinguish the 5-12-13 right-angled triangle
and then cosØ = adjacent/hypotenuse
x = 5, r = 13 , y = -12, since Ø is in IV
and sinØ = -12/13
also tan(ϕ) = −√15 = -√15/1 = y/x and ϕ is in II,
y = √15 , x = -1
r^2 = x^2 + y^2 = 15+1 = 16
r = 4
sinϕ = √15/4 , cosϕ = -1/4
you must know that:
cos(θ − ϕ) = cosθcosϕ + sinθsinϕ
= (5/13)(-1/4) + (-12/13)(√15/4)
= -5/52 - 12√15/52
= (-5-12√15)/52
