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3 years ago

Need help 27=6+7∣5−4x∣

1 answer:

3 0

$27 = 6 + 7(5 - 4x) \\ = > 27 = 6 + 35 - 28x \\ = > 28x = 6 + 35 - 27 \\ = > 28x = 14 \\ = > x = \frac{14}{28} = \frac{1}{2} = 0.5$

<h3>The answer is 0.5</h3>

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How do you do question 3 ?

Zolol [24]

x² - 4x + 8 → there are 3 terms (remember to include the sign with each term)

term 1: x²

term 2: -4x

term 3: 8

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4 years ago

What is the down payment of the sale price

amm1812

Answer:

The down payment is the lower of sale price and appraised value less the loan amount. It is not the same as the borrower's cash outlay if some of that outlay is used for settlement costs. Financing settlement costs does not affect the down payment.

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3 years ago

Jorge has $138.22 in his savings account. He deposits $10.75 every week and withdraws $31.68 every four weeks. What will his bal

spayn [35]

Answer:

Pretty sure the answer is $160.86

Step-by-step explanation:

you start off by multiplying 10.75 x 8 because that's how much he'll deposit at the end of an 8 week spand.

adding 86+138.22= 224.22

then you subtract 31.68 two times from that as he withdraws 2 times in the 8 weeks, giving you the answer of 160.86.

hope this helps xx have a good day :)

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3 years ago

Read 2 more answers

Which choice is similar to the figure shown?

IRINA_888 [86]

Answer:

The parallelogram whose sides are 5 and 20 is similar

Step-by-step explanation:

The parallelogram whose sides are 5 and 20 is similar to the given parallelogram whose sides are 2 and 8 because the figures are the same shade and corresponding sides are proportional.

$\frac{2}{5} = \frac{8}{20}$ $\frac{2}{4} \neq \frac{8}{18}$

$\frac{2}{5} =\frac{2}{5}$ $\frac{2}{4} \neq \frac{8}{4}$

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2 years ago

BRAINLIESTTT ASAP! PLEASE HELP ME :)

labwork [276]

Answer:

$\large \boxed{\text{5.2 lb$\cdot$in}^{-2}}}$

Step-by-step explanation:

In a direct proportion,

Pressure = constant × temperature

p = kT

We can use the initial conditions to find the value of k, and then calculate the pressure at the new temperature.

1. Determine the value of k

Data:

p₁ = 6 lb·in⁻²

T₁ = 440 K

Calculation:

$\begin{array}{rcl}p_{1} & = &k \times T_{1}\\6 & = &k \times 440\\k & = & \dfrac{6}{440}\end{array}$

2.Calculate the new pressure

$\begin{array}{rcl}p_{2} & = &k \times T_{2}\\& = &\dfrac{6}{440} \times 380\\\\& = & \mathbf{5.2}\end{array}\\\text{The new pressure is $\large \boxed{\textbf{5.2 lb$\cdot$in}^{\mathbf{-2}}}$}$

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4 years ago