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grigory [225]
3 years ago
10

Evaluate the piecewise function at x = -8 and x=8

Mathematics
1 answer:
Illusion [34]3 years ago
3 0

f(-8)=(-8)^3=-512\\\\
f(8)=\sqrt[3]8=2

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Original price $90 markdown 24%​
Gre4nikov [31]
The markdown will be $21.60. so the final price after the markdown is $68.40.
8 0
3 years ago
What is the result of adding these two equations?<br> −5x−9y=3<br> 5x−9y=−2<br> ​
dlinn [17]

Answer:

-18y = 1

Step-by-step explanation:

4 0
3 years ago
8(3)-3y=12 <br> What is y in this equation
iVinArrow [24]
8(3) - 3y = 12

First, multiply 8 × 3 to get 24.
24 - 3y = 12
Second, subtract '24' from both sides.
-3y = 12 - 24
Third, subtract '12 - 24' to get '-12'.
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Fourth, divide both sides by '-3'.
y =  \frac{-12}{-3}
Fifth, change the whole fraction to a negative.
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Sixth, 12 ÷ 3 = 4. Simplify your fraction to 4.
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3 0
3 years ago
Read 2 more answers
On highway 77, the Dobson exit is halfway between the Mt. Airy exit and the Elkin exit. If the Elkin exit is located at (-5,-2)
Leya [2.2K]

Given :

The Dobson exit is halfway between the Mt. Airy exit and the Elkin exit. If the Elkin exit is located at (-5,-2) and the Dobson exit is located at (-1,4).

To Find :

How far is it from the Elkin exit to the Mt. Airy exit.

Solution :

E(-5,-2) , D(-1 ,4 ) .

It is also given that Dobson exit is halfway between the Mt. Airy exit and the Elkin exit.

Let , location of Elkin exit is A(h,k) .

So , point D in terms of A and E is given by :

(\dfrac{h-5}{2},\dfrac{k-2}{2}) .

Comparing it with given D :

\dfrac{h-5}{2}=-1\\\\h=3 \dfrac{k-2}{2}=4\\\\k=10

Therefore , the location of Mt. Airy exit is ( 3, 10 ) .

Distance between Elkin exit to the Mt. Airy exit.

D=\sqrt{(5-3)^2+(-2-10)^2}\\\\D=12.17\ units

Therefore , distance between Elkin exit to the Mt. Airy exit is 12.17 units .

Hence ,this is the required solution .

4 0
3 years ago
Vicky starts a new job with an hourly pay of 7.15$. Suppose that her hourly pay increases by 5% each year. What will Vicky’s hou
Bingel [31]

Answer:

$8.28

Step-by-step explanation:

This is a compound growth problem.

The formula is:

F=P(1+r)^t

Where F is the future amount (amount in 3 yrs)

P is the initial amount (here, it is 7.15)

r is the rate of growth, in decimal (5% means 5/100 = 0.05)

t is the time , in years ( t = 3)

Now, substituting, we find the hourly wage after 3 years:

F=P(1+r)^t\\F=7.15(1+0.05)^3\\F=7.15(1.05)^3\\F=8.28

Hence,

<u>after 3 years, at 5% growth, the new hourly wage would be $8.28</u>

7 0
3 years ago
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