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denis-greek [22]
3 years ago
10

Find the value of x (Round to the nearest tenth) Help plssssssssss

Mathematics
1 answer:
max2010maxim [7]3 years ago
8 0

Answer:

bbhwhehwyayyquqysyegegegsgsgsgsusus

Step-by-step explanation:

vgsgahah z z zb

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Simplify the following expression:
Phantasy [73]
\frac{4}{ \frac{1}{4} - \frac{5}{2} }

To begin, we can simplify the expression's denominator by finding a common denominator between the denominators of the fractions in the denominator.  To make them compatible, we can convert \frac{5}{2} into \frac{10}{4}:

\frac{4}{ \frac{1}{4} - \frac{5}{2}( \frac{2}{2}) } = \frac{4}{ \frac{1}{4} - \frac{10}{4} }

Next, we can simplify:

\frac{4}{ \frac{1}{4} - \frac{10}{4} } = \frac{4}{ -\frac{9}{4}}

Finally, to cancel the denominator within the denominator, we can multiply the whole expression by \frac{4}{4}, or 1:

\frac{4}{ -\frac{9}{4}}* \frac{4}{4} =  -\frac{16}{9}

The expression simplifies to -\frac{16}{9}, or -1 \frac{7}{9} as a mixed number.
6 0
3 years ago
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Can you help me please to prove that the bleu areas are same without without useing numbers.
Nikitich [7]

Answer:

Answer

1

Answer:

they ate the some area just one is

stretched out more than the other one

Just draw a line from point D join to point

E

The triangle formed DME will be

congruent to AMC

Explanation:

3 0
2 years ago
ORDERING REAL NUMBERS
Bess [88]
3/25, 0.1, -√86, -9.34
4 0
3 years ago
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an angle bisector of a triangle divides the opposite side of the triangle into segments 6 cm and 5cm long. A second side of the
rodikova [14]
There is a not so well-known theorem that solves this problem.

The theorem is stated as follows:
"Each angle bisector of a triangle divides the opposite side into segments proportional in length to the adjacent sides"  (Coxeter & Greitzer)

This means that for a triangle ABC, where angle A has a bisector AD such that D is on the side BC, then 
BD/DC=AB/AC

Here either
BD/DC=6/5=AB/AC, where  AB=6.9,  
then we solve for  AC=AB*5/6=5.75,

or

BD/DC=6/5=AB/AC, where  AC=6.9,  
then we solve for AB=AC*6/5=8.28

Hence, the longest and shortest possible lengths of the third side are
8.28 and 5.75 units respectively.

4 0
3 years ago
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( 1 + 1 ) + ( 1 + 1 ) in standard form
san4es73 [151]

Answer:

4

Step-by-step explanation:

Standard form, in other words, is when it is fully simplified.

     [Given]

           ( 1 + 1 ) + ( 1 + 1 )

     [Add what it is the parentheses]

           ( 2 ) + ( 2 )

           2 + 2

     [Add 2 and 2 together]

           4

8 0
2 years ago
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