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gtnhenbr [62]
3 years ago
11

Which of the following circumstances would likely make factoring the best method for solving a quadratic equation?

Mathematics
1 answer:
BabaBlast [244]3 years ago
3 0

Answer:

The correct option is;

B. The difference of 2 perfect squares

Step-by-step explanation:

Solving a quadratic equation using factoring involves finding the factors of the equation that would yield the result of the quadratic equation

In order to find the roots of the quadratic equation, then the result of the factoring must be equal to zero, in which case, the constant terms in the factors are the solutions of the quadratic equation in opposite sign.

For example, we have;

x² - 5² = 11

We subtract 11 from both sides to get;

x² - 5² - 11  = 11 - 11

x² - 36 = 0

x² - 6² = 0

(x - 6) × (x + 6) = 0

Therefore, x = 6 or -6 which are the opposite sign of the constant terms in the factor.

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Trigonometry answer need
Sladkaya [172]
That is the answer..............
3 0
3 years ago
I know you add it but can you please help and show work
kondaur [170]
Answer is b i know this
5 0
4 years ago
Which inequality has –12 in its solution set? A B C D
Feliz [49]

Answer:

Step-by-step explanation:

solve each inequality:

A : x+6<8  ,  x<-8-6 , x<-14

B: x+4≥-6 ,  x≥-10

C: x-3>-10 , x>-7

D:x≤-9

since -12 is on the left side of the number line then x≤ -9 would be the solution

7 0
3 years ago
Read 2 more answers
A coin is tossed 11 times. a) How many different outcomes are possible? b) How many different outcomes have exactly 8 heads? c)
larisa86 [58]

Answer:

a) 2048

b)164

c)54

d) 11

Step-by-step explanation:

a) A coin has two faces.

Outcome possible =2^11= 2048

b) 8 heads possible outcome = 11!/8!3! = 3971688/241/920= 164 ways

c)2 heads outcome= 11!/2!8!= 39716800/725760=54

d) 7 heads= 11!/7!6! =39716800/3628800 = 11

5 0
3 years ago
Read 2 more answers
If a manufacturer conducted a survey among randomly selected target market households and wanted to be 95​% confident that the d
katen-ka-za [31]

Answer:

We need a sample size of least 119

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

Sample size needed

At least n, in which n is found when M = 0.09

We don't know the proportion, so we use \pi = 0.5, which is when we would need the largest sample size.

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.09 = 1.96\sqrt{\frac{0.5*0.5}{n}}

0.09\sqrt{n} = 1.96*0.5

\sqrt{n} = \frac{1.96*0.5}{0.09}

(\sqrt{n})^{2} = (\frac{1.96*0.5}{0.09})^{2}

n = 118.6

Rounding up

We need a sample size of least 119

6 0
3 years ago
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