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2 years ago

What value of x is in the solution set of 8x – 6 > 12 + 2x? –1 0 3 5

Mathematics

1 answer:

Tcecarenko [31]2 years ago

3 0

Value of 3 is in the solution set

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Hey luvs!

juin [17]

Answer:

I don't know I'm sorry.............

6 0

2 years ago

What is the equation of the line that passes through <br><br> (−3,5) and has a slope of<br> −2?

Tatiana [17]

Answer:

y-5=-2(x+3)

Step-by-step explanation:

y-y1=m(x-x1)

m=-2

y-5=-2(x-(-3))

y-5=-2(x+3)

5 0

2 years ago

How many 3 digit palindromes are divisible by 9?

ludmilkaskok [199]

Interesting problem.

A palindrome is a number which is identical when read/interpreted left-to-right or right-to-left. For example, 14241 is a palindrome, so is 444444.

A three digit palindrome must be made up of two distinct digits only, one for the first and last digits, and one for the middle, for example, 424, or 515, etc.

For a number to be divisible by 9, the sum of the digits must add up to a multiple of 9, such as 0, 9, 18, 27, etc.

We can now form a table of the possible 3-digit palindromes divisible by 9, starting with the first/last digits (=A), and finding the middle digit (=B). The number is therefore represented by the pattern ABA.

For example, when A=1, we have the number 1B1. For the number to be divisible by 9, B=7 so that sum=1+7+1=9, which is divisible by 9.

For each value of A (from 1 to 9) we can only find one value of B that makes the number divisible by 9. Thus we can only find nine such numbers, with A equal to 1 to 9.

Here's a list of the numbers

A B number

1 7 171

2 5 252

3 3 333

4 1 414

5 8 585

6 6 666

7 4 747

8 2 828

9 0 909

3 0

3 years ago

A flash disk has the capacity of storing 1 megabyte of data. How many kilobytes of data can be stored in the same flash disk

Luden [163]

For this sort of problem, you need to be familiar with prefixes.

So:

megabyte = $1 *10^6$ bytes

kilobyte = $1*10^3$ bytes

and a regular byte would just be $1$

Now, you will need to do a conversion:

$1megabyte*\frac{1*10^6bytes}{1megabyte}*\frac{1*10^{-3}kilobyte}{1byte}$

I'm going to explain this just in case, but we convert megabytes to regular bytes in the first half by using the information I gave you above. (In one megabyte, there are $1*10^6$ bytes!)

In the second fraction thought, remember one kilobyte is $1*10^3$ bytes. However, you usually only see one of each thing on the bottom of fractions, so you need to add a negative sign to the 3. (technically you could just do $\frac{1kilobyte}{1*10^3bytes}$ , but I think it is more correct to do write it out how I did).