Answer:
a5 = 2604
Step-by-step explanation:
a1 = 4
a2 = -5(4)-1 = -21
a3 =-5(-21)-1 = 104
a4 = -5(104)-1 =-521
a5 =-5(-521)-1 = 2604
Answer is 553 beasts
Step by step:
Multiply 158 by 3 to get 474
Divide 158 by 2 to get 79
Add 474 with 79 and get 553
That's for the equation I got from the picture
<span>Lets say the 1st die rolled a 2 -
there would be 2 combinations for which the sum of dice being < 5 :
2,1
2,2
Now say the 2nd die rolled a 2 -
there would be 2 combinations for which the sum of dice being < 5 :
1,2
2,2
Now we want to count all cases where either dice showed a 2 and sum of the dice was < 5. However note above that the roll (2,2) is counted twice.
So there are three unique dice roll combinations which answer the criteria of at least one die showing 2, and sum of dice < 5:
1,2
2,1
2,2
The total number of unique outcomes for two dice is 6*6=36 .
So, the probability you are looking for is 3/36 = 1/12</span>
<h2>1/4 or 0.25</h2>
Step-by-step explanation:
Convert Mixed number to improper fraction.
Equate
Cross Multiply
Divide both sides of the equation by 40
Simplify
