Answer:
Area = 213.18
Step-by-step explanation:
11.4 x 18.7 = 213.18
Hope this helps you! :)
The formula for direct variation is y = kx<span> where k </span>≠ 0
y = 9/x is an inverse relation
Complete question is:
Seventy million pounds of trout are grown in the U.S. every year. Farm-raised trout contain an average of 32 grams of fat per pound, with a standard deviation of 7 grams of fat per pound. A random sample of 34 farm-raised trout is selected. The mean fat content for the sample is 29.7 grams per pound. Find the probability of observing a sample mean of 29.7 grams of fat per pound or less in a random sample of 34 farm-raised trout. Carry your intermediate computations to at least four decimal places. Round your answer to at least three decimal places.
Answer:
Probability = 0.0277
Step-by-step explanation:
We are given;
Mean: μ = 32
Standard deviation;σ = 7
Random sample number; n = 34
To solve this question, we would use the equation z = (x - μ)/(σ/√n) to find the z value that corresponds to 29.7 grams of fat.
Thus;
z = (29.7 - 32)/(7/√34)
Thus, z = -2.3/1.200490096
z = -1.9159
From the standard z table and confirming with z-calculator, the probability is 0.0277
Thus, the probability to select 34 fish whose average grams of fat per pound is less than 29.7 = 0.0277
Answer:
A. 
B. 
Step-by-step explanation:
A. The area of the shaded region = area of the whole large square - area of the 4 smaller squares
= (5x*5x) - 4(4*4)
Area of shaded region = 
B. The expression, , is the difference of two perfect squares, 25x² and 64. Therefore, apply the rule of factoring difference of two perfect squares.
Thus, 
Therefore, the expression of the are of the shaded region can be expressed in factored form as:
