Let L and S represent the weights of large and small boxes, respectively. The problem statement gives rise to two equations:
.. 7L +9S = 273
.. 5L +3S = 141
You can solve these equations various ways. Using "elimination", we can multiply the second equation by 3 and subtract the first equation.
.. 3(5L +3S) -(7L +9S) = 3(141) -(273)
.. 8L = 150
.. L = 150/8 = 18.75
Then we can substitute into either equation to find S. Let's use the second one.
.. 5*18.75 +3S = 141
.. S = (141 -93.75)/3 = 15.75
A large box weighs 18.75 kg; a small box weighs 15.75 kg.
Answer: 648 pull-ups
Step-by-step explanation:
Given
Max take 5.5 minutes to do 60 Pull-ups with a break in between
Similarly, it took 8 minutes for 120 pull-ups
Suppose the time taken for a single pull-up and break is x and y minutes
So, it can be written

Now, suppose max perform at this rate, and the total pull-ups are P in 30 minutes

Answer:
(29.46 mm, 29.54 mm).
Step-by-step explanation:
We have the standard deviation for the sample, so we use the t-distribution to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 43 - 1 = 42
95% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 42 degrees of freedom(y-axis) and a confidence level of
. So we have T = 2.018
The margin of error is:

In which s is the standard deviation of the sample and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 29.5 mm - 0.04mm = 29.46 mm
The upper end of the interval is the sample mean added to M. So it is 29.5 mm + 0.04mm = 29.54 mm
The 95% confidence level for the true mean width is: (29.46 mm, 29.54 mm).
Answer:
.05
Step-by-step explanation:
you divide 5 by 100 which makes it .05