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Sauron [17]
3 years ago
15

A shirt that normally costs $30 is on sale for $21.75. What percent of the regular price is the sale price?

Mathematics
1 answer:
disa [49]3 years ago
8 0

First you divide sale cost which is $21.75 by the original cost of the shirt being $30.

Once you divide 21.75 into 30 dollars you'll get 0.725

Now you wanna multiply that 0.725 by 100% which will then

give you the total 72.5%

________________________

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Jamie purchased a condo in Naples, Florida, for $699,000. She put 20% down and financed the rest at 5% for 35 years. What are Ja
EleoNora [17]
The payments are ...
  A = P(r/n)/(1 -(1+r/n)^(-nt))
where P is the principal amount, $699,000*0.80 = $559,200
  r is the annual interest rate, 0.05
  n is the number of compoundings per year, 12
  t is the number of years.
Then
  A = 559,200*(0.05/12)/(1 -(1 +0.05/12)^(-12*35)) = 2822.21

The total of 420 of these payments is $1,185,328.20, which is $626,128.20 more than the loan amount.

Jamie's total finance charge is about $626,128.20.


_____
There is always some minor adustment required in the amount of the last payment. That has not been taken into account here.
8 0
3 years ago
Find the equation of a line with a slope of 1 and passing through (11;3)
romanna [79]

Step-by-step explanation:

slope(m)=(Y-Y1)/X-X1

here,

M=1

(X1,Y1)=(11,3)

NOW,

m=(Y-Y1)/(X-X1)

1=(Y-3)/(X-11)

1×(X-11)=Y-3

X-11=Y-3

X-Y-11+3=0

X-Y-8=0

X-Y=0 is the required equation.

3 0
3 years ago
Bill and Amy want to ride their bikes from their neighborhood to school which is 14.4 km away. It takes Amy 40 minutes to arrive
vfiekz [6]

Answer:

Amy is (21.6 - 14.4) 7.2 km/hr faster than Bill.

Distance = speed / time

Amy's speed

40 minutes = 40/60 = 2/3 hours

14.4 = speed / 2/3

Speed = 14.4 * 3/2 = 21.6 km/ hr

Bill speed

60 minutes = 1 hour

Speed = 14.4 km / hr.

4 0
3 years ago
What are the coordinates of A?
Nitella [24]

Answer:

The coordinates of A could be anything in the form of (x, y, z) if you have a third axis. First you count where A is on the x-axis then the y-axis and if you have a 3-dimensional graph then the z-axis.

Step-by-step explanation:

3 0
3 years ago
*Asymptotes*<br> g(x) =2x+1/x-3 <br><br> Give the domain and x and y intercepts
Nataly [62]

Answer: Assuming the function is g(x)=\frac{2x+1}{x-3}:

The x-intercept is (\frac{-1}{2},0).

The y-intercept is (0,\frac{-1}{3}).

The horizontal asymptote is y=2.

The vertical asymptote is x=3.

Step-by-step explanation:

I'm going to assume the function is: g(x)=\frac{2x+1}{x-3} and not g(x)=2x+\frac{1}{x}-3.

So we are looking at g(x)=\frac{2x+1}{x-3}.

The x-intercept is when y is 0 (when g(x) is 0).

Replace g(x) with 0.

0=\frac{2x+1}{x-3}

A fraction is only 0 when it's numerator is 0.  You are really just solving:

0=2x+1

Subtract 1 on both sides:

-1=2x

Divide both sides by 2:

\frac{-1}{2}=x

The x-intercept is (\frac{-1}{2},0).

The y-intercept is when x is 0.

Replace x with 0.

g(0)=\frac{2(0)+1}{0-3}

y=\frac{2(0)+1}{0-3}  

y=\frac{0+1}{-3}

y=\frac{1}{-3}

y=-\frac{1}{3}.

The y-intercept is (0,\frac{-1}{3}).

The vertical asymptote is when the denominator is 0 without making the top 0 also.

So the deliminator is 0 when x-3=0.

Solve x-3=0.

Add 3 on both sides:

x=3

Plugging 3 into the top gives 2(3)+1=6+1=7.

So we have a vertical asymptote at x=3.

Now let's look at the horizontal asymptote.

I could tell you if the degrees match that the horizontal asymptote is just the leading coefficient of the top over the leading coefficient of the bottom which means are horizontal asymptote is y=\frac{2}{1}.  After simplifying you could just say the horizontal asymptote is y=2.

Or!

I could do some division to make it more clear.  The way I'm going to do this certain division is rewriting the top in terms of (x-3).

y=\frac{2x+1}{x-3}=\frac{2(x-3)+7}{x-3}=\frac{2(x-3)}{x-3}+\frac{7}{x-3}

y=2+\frac{7}{x-3}

So you can think it like this what value will y never be here.

7/(x-3) will never be 0 because 7 will never be 0.

So y will never be 2+0=2.

The horizontal asymptote is y=2.

(Disclaimer: There are some functions that will cross over their horizontal asymptote early on.)

6 0
3 years ago
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