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3 years ago

Please help vvvvvvvvvvv

Mathematics

1 answer:

Anuta_ua [19.1K]3 years ago

7 0

Answer:

Step-by-step explanation:

since you are subtracting a negative number it reverses, so you actually ADD the two together

so, 12 1/2 + 4 1/2

add the whole numbers first;

12+4=16

then fractions:

1/2 + 1/2= 1

then all together;

16+1=17!

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What's the y intercept of the following equation? 10y = 20x + 30

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Answer:

$10y = 20y + 30 \\ y = 2y + 3 \\ y \: intercep = 3$

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2 years ago

A fair die is rolled once. Let A be the event of rolling an even number, and let B be the event of rolling a number greater than

IRISSAK [1]

Answer:

A ∩ B = {4, 6}

Step-by-step explanation:

A die had 6 faces

S = {1, 2, 3, 4, 5, 6}

If A be the event of rolling an even number, then;

A = {2, 4, 6}

If B be the event of rolling a number greater than 3, then;

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2 years ago

P/-8 + 9 > 13 pls explain i don't get it

KonstantinChe [14]

Answer:

p < -32

Step-by-step explanation:

Given: p/-8 + 9 > 13

Rewrite: $\frac{p}{-8}$ + 9 > 13

Subtract 9 from both sides: $\frac{p}{-8}$ > 4

Move the negative (it is a fraction): $\frac{-p}{8}$ > 4

Multiply both sides by 8: -p > 32

Times by -1 (-p -> -1p): p > -32

Flip the sign (multiplied by a negative): p < -32

Hope this helps, have a nice day :D

3 0

2 years ago

Read 2 more answers

The function g(x) = 12,500(0.91)x represents the value of a piece of farm equipment after x years. Approximately when will its v

topjm [15]

Answer:

B. 7.3 years

Step-by-step explanation:

The question is wrong. The correct function is :

$g(x)=12500(0.91)^{x}$

We have the function $g(x)$ that represents the value of a piece of farm equipment after $x$ years.

This means that when $x=0$ its original value is :

$g(0)=12500(0.91)^{0}=12500$

Now we want to calculate approximately when will its value be half its original value. Then, we write :

$\frac{12500}{2}=6250$

$6250$ is half of its original value. We need to find $x$ that satisfies the following equation :

$g(x)=6250=12500(0.91)^{x}$

Solving for $x$ :

$6250=12500(0.91)^{x}$ ⇒

$0.5=(0.91)^{x}$

Now we apply natural logarithm to each side of the equation :

$ln(0.5)=ln[(0.91)^{x}]$

Using logarithm properties :

$ln(0.5)=ln[(0.91)^{x}]$ ⇒

$ln(0.5)=x[ln(0.91)]$

$x=\frac{ln(0.5)}{ln(0.91)}$ ⇒

$x$ ≅ $7.3496$

The correct option is B. 7.3 years

4 0

2 years ago