Answer:
The period, in seconds to two decimal places is, 2.84 sec
Step-by-step explanation:
Using formula:
......[1]
where
T represents the Time period in second
l represents the length of the pendulum/
As per the statement:
Use the gravitational constant g = 9.8 m/s^2 , length of the simple pendulum(l) = 2 meters and ![\pi = 3.14](https://tex.z-dn.net/?f=%5Cpi%20%3D%203.14)
Substitute the given values we have;
![T = 2\cdot 3.14 \cdot \sqrt{\frac{2}{9.8}}](https://tex.z-dn.net/?f=T%20%3D%202%5Ccdot%203.14%20%5Ccdot%20%5Csqrt%7B%5Cfrac%7B2%7D%7B9.8%7D%7D)
⇒![T = 6.28 \cdot \sqrt{\frac{1}{4.9}}=6.28 \cdot \frac{1}{2.21359436212}= \frac{6.28}{2.21359436212} = 2.83701481512](https://tex.z-dn.net/?f=T%20%3D%206.28%20%5Ccdot%20%5Csqrt%7B%5Cfrac%7B1%7D%7B4.9%7D%7D%3D6.28%20%5Ccdot%20%5Cfrac%7B1%7D%7B2.21359436212%7D%3D%20%5Cfrac%7B6.28%7D%7B2.21359436212%7D%20%3D%202.83701481512)
Therefore, the period, in seconds to two decimal places is, 2.84 sec
The complete question is :
Question: What is the coefficient in the expression 10x²-7?
The coefficient in the expression
is 10
<h3>What is Coefficient?</h3>
A numerical or constant quantity placed before and multiplying the variable in an algebraic expression.
According to the question,
The expression given is ![10x^{2} -7](https://tex.z-dn.net/?f=10x%5E%7B2%7D%20-7)
The variable given is x
We need to find the coefficient in the expression.
In the given expression x is the variable and the number before the x is coefficient which is 10 .
Hence the coefficient in the expression is 10.
Learn more about coefficient here:
brainly.com/question/22241464
#SPJ1
Answer:
Yes
Step-by-step explanation:
An integer is any whole number.
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Answer:
The equation for regression line and predicting a husband's height for married couples in their early 20s
Equation: Y'=33.67+0.54*X'
Step-by-step explanation:
r=0.5
x'=64.5
Sx=2.5
y'=68.5
Sy=2.7
General regression line equation is:
Y'=a+b*X'
so the slope of the regression line is the linear correlation coefficient multiplied by the standard deviation for y' divided by the standard deviation for x'
![b=r*\frac{S_{y}}{S_{x}}\\b=0.5*\frac{2.7}{2.5}\\b=0.54](https://tex.z-dn.net/?f=b%3Dr%2A%5Cfrac%7BS_%7By%7D%7D%7BS_%7Bx%7D%7D%5C%5Cb%3D0.5%2A%5Cfrac%7B2.7%7D%7B2.5%7D%5C%5Cb%3D0.54)
The intercept with axis y is the mean of the decreased by the product of the slope and the mean of x
![a=y'-b*x'\\a=68.5-0.54*64.5\\a=33.67](https://tex.z-dn.net/?f=a%3Dy%27-b%2Ax%27%5C%5Ca%3D68.5-0.54%2A64.5%5C%5Ca%3D33.67)
The equation regression line then is:
Y'=33.67+0.54*X'