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3 years ago

I keep forgetting how to do these sighs

Mathematics

2 answers:

goblinko [34]3 years ago

8 0

If you plugged in and solved for x correctly, you should get 120°

trapecia [35]3 years ago

7 0

RSU+UST=RST
78+3x-12=6x+12
3x+66=6x+12
3x=54
x=18
108+12=120
∠RST=120°

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The weight of an object on the moon varies directly with its weight on the earth. If an object weighing 95 lbs on the moon weigh

Luda [366]

ANSWER

450lb

EXPLANATION

If the weight, m of an object on the moon varies directly as the weight of an object e, on the earth, then we can write the mathematical statement,.
$m \propto \: e$
We introduce the constant of proportionality to obtain,

$m = ke$

When, m=95, e=570,

This implies that,

$95 = 570k$
$k = \frac{95}{570}$

$k = \frac{1}{6}$

The equation now becomes,

$m = \frac{1}{6} e$

We want to find e, when m=2700,

$m = \frac{1}{6} \times 2700$

$m =450lb$

8 0

3 years ago

Pine Street intersects Center Street at a 65 degree angle. If center Street is parallel to First Avenue, which equation is true?

Nimfa-mama [501]

The answer would be x=180-65 this is because vertically opposite angle to 65 would be 65 which means that x and 65 are supplementary.

5 0

3 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=F%28x%29%20%3D%20%5Cfrac%7Bx%5E%7B3-8%7D%20%7D%7Bx%5E%7B2%7D%20-6x%2B8%7D" id="TexFormula1" ti

Firlakuza [10]

Answer:

Domain: All the real values except x = 2 and x = 4: R - {2, 4}
Holes: x = 2
VA, vertical asymptores: x = 4
HA: horizontal asymptotes: there are not horizontal asymptotes
OA: oblique asymptotes: x + 6 [note that OH does not stand for any known feature, and so it is understood that it was intended to write OA]
Roots: x = 2
Y-intercept: -1

Step-by-step explanation:

1. Given:

$f(x)=\frac{x^3-8}{x^2-6x+8}$

Note that the number 8 in the numerator is not part of the power.

Type of function: rational function

2. Domain: is the set of x-values for which the function is defined.

The given function is defined for all x except those for which the denominator equals 0.

Denominator: x² -6x + 8 = 0

Solve for x:

Factor. (x - 4 )(x - 2) = 0

Zero product property: (x - 4) = 0 or (x - 2) = 0

x - 4 = 0 ⇒ x = 4

x - 2 = 0 ⇒ x = 2

Domain:

All the real values except x = 2 and x = 4: x ∈ R / x ≠ 2 and x ≠ 4.

3. Holes:

The holes on the graph of a rational function are at those x-values for which both the numerator and denominator are zero.

Find the values for which the numerator is zero:

Numerator: x³ - 8 = 0

Factor using difference of cubes property:

a³ - b³ = (a - b)(a² + ab + b²)

x³ - 8 = (x - 2)(x² + 2x + 4) = 0

Zero product property: (x - 2)(x² + 2x + 4) = 0

x - 2 = 0 ⇒ x = 2

x² + 2x + 4 = 0 (this has not real solution)

The values for which the denominator is zero were determined above: x = 2 and x = 4.

Conclusion: for x = 2 both numerator and denominator equal 0, so this is a hole.

4. VA: Vertical asymptotes.

The vertical asymptotes on the graph of a rational function are the vertical lines for which only the denominator (and not the numerator) equals zero.

In the previous part it was determined that happens when x = 4.

5. HA: Horizontal asymptotes.

In rational functions, if the numerator is a higher degree polynomial than the denominator, there is no horizontal asymptote.

6. OA: oblique asymptotes

Find the quotient and the remainder.

x + 6

_______________

x² - 6x + 8 ) x³ + 0x² + 0x - 8

- x³ + 6x² - 8x

___________

6 x² - 8x - 8

- 6x² + 36x - 48

_____________

28x - 56

Result: (x + 6) + (28x - 56) / (x² - 6x + 8)

Find limit x → ∞

$\lim_{x \to \infty}(x + 6) + \frac{28x-56}{x^2-6x+8}=x+6$

7. Roots:

Roots are the values for which f(x) = 0.

That happens when the numerator equals 0, and the denominator is not 0.

As determined earlier: x³ - 8 = 0 ⇒ x = 2.

8. Y-Intercept

The y-intercepts of any function are the y-values when x = 0

Substitute x = 0 into the function:

$f(x)=\frac{x^3-8}{x^2-6x+8}=\frac{0^3-8}{0^2-6(0)+8}}=\frac{-8}{8} =-1$

3 0

3 years ago

PLEASE HELP FAST simplify: sqrt 8 + 2 sqrt 15

Ket [755]

Answer:

2 $\sqrt{2}$ + 2 $\sqrt{15}$

Step-by-step explanation:

$\sqrt{8}$ = $\sqrt{4}$ $\sqrt{2}$ = 2 $\sqrt{2}$

7 0

2 years ago

Find the length of the third side. If necessary, round to the nearest tenth. 6 14

Romashka-Z-Leto [24]

Answer:

≈ 12.6

Step-by-step explanation:

Using Pythagoras' identity in the right triangle.

The square on the hypotenuse is equal to the sum of the squares on the other 2 sides.

let x be the third side, then

x² + 6² = 14²

x² + 36 = 196 ( subtract 36 from both sides )

x² = 160 ( take the square root of both sides )

x = $\sqrt{160}$ ≈ 12.6 ( to the nearest tenth )

8 0

2 years ago

I keep forgetting how to do these *sighs*

I keep forgetting how to do these sighs