The weights of the fish in a certain lake are normally distributed with a mean of 18 lb and a standard deviation of 12. if 16 fi
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Answer:
Step-by-step explanation:
A. H0: accident are evenly distributed
H1: accident are not evenly distributed
B. The critical value is chi²(0.01,7) = 18.4753
C. The decision rule would be to reject h0 and accept h1 if the test statistic is higher than the critical value
D. Test statistic = summation (Oi-Ei)²/E
This gives 24.6 from the table.
E. Based on these calculations, test statistic is > than critical value
24.6> 18.4753
F. The inference is that accidents are not evenly distributed at 0.01 level of significance.
