Triangle QRS has 3 congruent sides, so it is equilateral and equiangular.
The sum of the measures of the angles of a triangle is 180 deg, so each angle of triangle QRS is 60 deg.
Angle RQS measures 60 degrees and forms a linear pair with angle PQS. Angles in a linear pair a supplementary. That makes the measure of angle PQS 120 deg. leaving only 60 degrees as the sum of the measures of angles PSQ and SPQ. Triangle PQS is isosceles since sides PQ and QS are congruent. The angles opposite congruent sides of a triangle are congruent, so angle PSQ is congruent to angle SPQ. That means angles PSQ and SPQ measure 30 deg each.
m<PSR = m<PSQ + m<QSR = 30 + 60 = 90
m<PQS = 120
m<PSR : m<PQS = 90 : 120 = 3 : 4
No choice shows the correct answer.
Parallel lines have the same slope. The equation of the parallel line is therefore:
y = x + b
Plug in the values you are given to find b:
2 = -3 + b
b = 5
Answer:
408 cm^3
Step-by-step explanation:
You have to find the volume of each object individually. You first find the volume of the sphere, so you input the radius, which is 3, into the equation which comes out to be 108 cm^3. You then have to find the volume of the cylinder, and since you have the diameter of the cylinder, and you need the radius, and the radius is half of the diameter, you would input 5 into the equation as the radius, since half of 10 is 5. That comes out to be 300 cm^3, so then you add the two volumes together, which is 408 cm^3
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This is because the expression can be simplified to get the same result. -1+2log_4((1/4)x)
Answer:
Interquartile Range
Step-by-step explanation:
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