Find the exact area of a circle having the given circumference. 4(√3 π) A =

1 answer:

4 0

$\bf \textit{circumference of a circle}\\\\
C=2\pi r\qquad 
\begin{cases}
r=radius\\
----------\\
C=4\sqrt{3}\ \pi 
\end{cases}\implies 4\sqrt{3}\ \pi=2\pi r
\\\\\\
\cfrac{4\sqrt{3}\ \pi}{2\pi}= \boxed{r}\\\\
-----------------------------\\\\
\textit{area of a circle}\\\\
A=\pi r^2\qquad \boxed{r}=\cfrac{4\sqrt{3}\ \pi}{2\pi}\implies A=\pi \left( \cfrac{4\sqrt{3}\ \pi}{2\pi} \right)^2$

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Please help this is hard math

Rainbow [258]

Answer:

$y=-4x+2$

Step-by-step explanation:

First we find the slope of the line AB passing through the point (2,0)
line AB is perpendicular to the line $y=\frac{1}{4}x-3$ , this equation is slope intercept for, which is $y=mx+b$ so our m or slope is $\frac{1}{4}$
Since the slope of line AB is perpendicular to $m=\frac{1}{4}$ then we use the equation $slope of line1\times slopeofline2=-1$ , so what do we multiply $\frac{1}{4}$ by to get -1? -4 right, so that's the slope of line AB with the point (2,0)
Now line CD is parallel to line AB, that means it has the same slope as AB, so slope of CD is -4
So we make the equation $y-y_1=m(x-x_1)$ so m= -4 and our point is (-1,6)
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