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Mathematics

2 answers:

xz_007 [3.2K]3 years ago

5 0

Answer:

The answer is 24.

Step-by-step explanation:

Dahasolnce [82]3 years ago

3 0

Answer:

Step-by-step explanation:

I took the test on E2020.

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Write the equation of the line that passes through the point(-6,12) and is parallel to the line y=8

Ugo [173]

Answer:

y = 12

Step-by-step explanation:

y = 8 is the equation of a horizontal line, parallel to the x- axis.

Thus a parallel line will also be horizontal.

The equation of a horizontal line is

y = c

where c is the y- coordinates of the points it passes through.

The line passes through (- 6, 12) with y- coordinate of 12, thus

y = 12 ← equation of parallel line

5 0

3 years ago

What value of k makes the trinomial x^2- 10x + k a perfect square?

Advocard [28]

Answer: 25

Step-by-step explanation: (x-a)² = x² - 2ax + a²

From x² - 10x + k we deduce that 10x = 2·5x and a = 5

Then k = 5²2

3 0

3 years ago

What is lim x→3 x^2 - x - 6/ x - 3

Kisachek [45]

<h3>Answer: D) 5</h3>

=======================================================

Explanation:

If we plugged x = 3 into the expression, then we'd get x-3 = 3-3 = 0 in the denominator. That's not allowed. But we can simplify first

x^2-x-6 factors to (x-3)(x+2). The key here is that (x-3) is a factor. It cancels with the x-3 in the denominator

So, $\frac{x^2-x-6}{x-3} = \frac{(x-3)(x+2)}{x-3} = x+2$

Allowing us to say,

$\displaystyle \lim_{x \to 3}\frac{x^2-x-6}{x-3} = \lim_{x \to 3}\frac{(x-3)(x+2)}{x-3}\\\\\\\displaystyle \lim_{x \to 3}\frac{x^2-x-6}{x-3} = \lim_{x \to 3}(x+2)\\\\\\\displaystyle \lim_{x \to 3}\frac{x^2-x-6}{x-3} = 3+2\\\\\\\displaystyle \lim_{x \to 3}\frac{x^2-x-6}{x-3} = 5\\\\\\$