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uranmaximum [27]
3 years ago
9

Factor: 2x^2+ 5x-3=0

Mathematics
1 answer:
egoroff_w [7]3 years ago
5 0

Answer:

x=1/2or x=−3

Step-by-step explanation:

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Can somebody please help me
erik [133]

Answer:

d=3 and e=-1

Step-by-step explanation:

d+e=2

d=2-e-----(1)

d-e=4-----(2)

substituting (1) in (2)

2-e-e=4

-2e=2

e=-1-----(3)

substituting (3) in (1)

d=2-(-1)

d=3

6 0
3 years ago
For what value of constant c is the function k(x) continuous at x = 0 if k =
nlexa [21]

The value of constant c for which the function k(x) is continuous is zero.

<h3>What is the limit of a function?</h3>

The limit of a function at a point k in its field is the value that the function approaches as its parameter approaches k.

To determine the value of constant c for which the function of k(x)  is continuous, we take the limit of the parameter as follows:

\mathbf{ \lim_{x \to 0^-} k(x) =  \lim_{x \to 0^+} k(x) =  0 }

\mathbf{\implies  \lim_{x \to 0 } \ \  \dfrac{sec \ x - 1}{x}= c }

Provided that:

\mathbf{\implies  \lim_{x \to 0 } \ \  \dfrac{sec \ x - 1}{x}= \dfrac{0}{0} \ (form) }

Using l'Hospital's rule:

\mathbf{\implies  \lim_{x \to 0} \ \  \dfrac{\dfrac{d}{dx}(sec \ x - 1)}{\dfrac{d}{dx}(x)}=  \lim_{x \to 0}   sec \ x  \ tan \ x = 0}

Therefore:

\mathbf{\implies  \lim_{x \to 0 } \ \  \dfrac{sec \ x - 1}{x}=0 }

Hence; c = 0

Learn more about the limit of a function x here:

brainly.com/question/8131777

#SPJ1

5 0
2 years ago
Three machines operating independently, simultaneously, and at the same constant rate can fill a certain production order in 36
Andrews [41]

Answer:

D

Step-by-step explanation:

Let the total production order be X. The combined rate is thus x/36 orders per hour.

Now, we know that the three machines are working at the same constant rate. This means that individual rate for each of the machines will be x/36 divided by 3 and that gives x/108 per machine.

Now, we are having another machine coming at the same constant rate. This means we are adding an x/108 rate to the preexisting x/36.

The new total rate thus becomes x/108 + x/36 = 4x/108

Now we know that the total new rate is 4x/108. Since the total work doesn’t change and it is still x, the time taken to complete a work of x orders at a rate of 4x/108 order per hour would be x divided by 4x/108 and this is x * 108/4x = 108/4 = 27 hours

7 0
3 years ago
-PA-Common Core Math 7 B
Fantom [35]

Answer:

Step-by-step explanation:

A-10.0 in

B-35 in

6 0
2 years ago
Plz can anyone help me?
Sati [7]

Answer:

400x

Step-by-step explanation:

as shown in the graph from points such as (1, 400) or (2,800) the person is traveling 400 per day

4 0
3 years ago
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