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Pavlova-9 [17]
3 years ago
9

Find the equation of the line that is perpendicular to the line x+3y+10=0 and goes through the point (5,-1)

Mathematics
1 answer:
brilliants [131]3 years ago
4 0

Answer:

Perpendicular line's gradient = -1/gradient

x+3y+10=0

3y = -x - 10

y = -⅓x - 10/3

gradient = -⅓

y = -⅓x + c

At 5,-1

-1 = -⅓(5) + c

-1 = -5/3 + c

-1 + 5/3 = c = ⅔

y = -⅓x + ⅔

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Suppose a circle has a radius of 13 inches. How far would a 24 inch chord be from the center of the circle? (Hint: Draw a diagra
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Answer:

Step-by-step explanation:

Directions

  • Draw a circle
  • Dear a chord with a length of 24 inside the circle. You just have to label it as 24
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Givens

AC = 13 inches                   Given

CB = 24 inches                  Given

CE = 12 inches                    Construction and property of a midpoint.

So what we have now is a right triangle (ACE) with the right angle at E.

What we seek is AE

Formula

AC^2 = CE^2 + AE^2

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169 - 144 = 144-144 + AE^2     Combine

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Answer

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