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agasfer [191]
3 years ago
14

If you roll three fair coins what is the probability that youll get at least 2 heads

Mathematics
2 answers:
blagie [28]3 years ago
6 0

Answer:

1/2 or 50%

Step-by-step explanation:

You can use some casework to find your answer.

The first case - only two of the coins are heads.

The possible ways that this could be are:

THH

HTH

HHT

The second case - all three coins are heads.

In this instance, there is only one way that this could happen:

HHH

This is a total of 4 desired outcomes out of 2*2*2=8 possible outcomes, which is a probability of 4/8=1/2. Hope this helps!

Dennis_Churaev [7]3 years ago
6 0

Answer:  12.5

Step-by-step explanation:

100/2=50/2=25/2=12.5

HOPE THIS HELP

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If a histogram is right skewed, which will be greater the mean or the median? Type a single word answer in the space
Mandarinka [93]

Answer:

Mean is greater

Step-by-step explanation:

For a skewed distribution, then the tail is longer to one side from the center than to the other. In a right skewed distribution, the tail is longer to the right.

When a distribution is skewed, the mean will be closer to the tail Than the median. Therefore. For a right skewed histogram, the mean is closer to the tail of the histogram and hence closer to the right. Once this happens, values closer to the right of a distribution are higher (number line). Thus the mean will be greater than the median.

8 0
3 years ago
I really need help quick
Natali [406]

Answer:

\sf x=2+\sqrt{6},\:x=2-\sqrt{6}

Explanation:

\sf y = x^2 -4x

given that y = 2

\sf x^2 -4x = 2

\sf x^2 -4x -2 = 0

using quadratic formula:

\sf x = \dfrac{ -b \pm \sqrt{b^2 - 4ac}}{2a}  \    \ \ when  \   ax^2 + bx + c = 0

\rightarrow \sf x_{1,\:2}=\dfrac{-\left(-4\right)\pm \sqrt{\left(-4\right)^2-4\cdot \:1\cdot \left(-2\right)}}{2\cdot \:1}

\rightarrow \sf x_1=\dfrac{-\left(-4\right)+2\sqrt{6}}{2\cdot \:1},\:x_2=\dfrac{-\left(-4\right)-2\sqrt{6}}{2\cdot \:1}

\rightarrow \sf x=2+\sqrt{6},\:x=2-\sqrt{6}

in decimals:

\rightarrow \sf x=4.45 , \ -0.45

5 0
2 years ago
The probability of Sandy flipping a coin twice and getting heads both times is 0.25. The probability of John's spinner stopping
Ede4ka [16]

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I think the answer is A but I could be wrong
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