Answer:
6776
Step-by-step explanation:
77
88
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8 times 7=56 8 times 70= 560 then add together so 616 next line 80 times 7= 560 80 times 70=5600 then add those together 6160 then add the too totals together 6160+ 616= 6776
Answer:
![Discriminant=0\\b)\ One\ Real\ Solution](https://tex.z-dn.net/?f=Discriminant%3D0%5C%5Cb%29%5C%20One%5C%20Real%5C%20Solution)
Step-by-step explanation:
![We\ are\ given\ that:\\4w^2+8w+4=0\\We\ know\ every\ quadratic\ equation\ can\ be\ represented\ in\ the\ form\ of:\\ax^2+bx+c=0,\ where\ x \neq 0\\Hence,\\Lets\ first\ recognize\ the\ co-efficients\ of\ the\ algebraic\ terms( x^2,\ x,\ x^0),\\ which\ are\ a,b\ and\ c\ respectively.](https://tex.z-dn.net/?f=We%5C%20are%5C%20given%5C%20that%3A%5C%5C4w%5E2%2B8w%2B4%3D0%5C%5CWe%5C%20know%5C%20every%5C%20quadratic%5C%20equation%5C%20can%5C%20be%5C%20represented%5C%20in%5C%20the%5C%20form%5C%20of%3A%5C%5Cax%5E2%2Bbx%2Bc%3D0%2C%5C%20where%5C%20x%20%5Cneq%200%5C%5CHence%2C%5C%5CLets%5C%20first%5C%20recognize%5C%20the%5C%20co-efficients%5C%20of%5C%20the%5C%20algebraic%5C%20terms%28%20x%5E2%2C%5C%20x%2C%5C%20x%5E0%29%2C%5C%5C%20which%5C%20are%5C%20a%2Cb%5C%20and%5C%20c%5C%20respectively.)
![Hence,\\4w^2+8w+4=0\\4(w^2)+8(w)+4(w^0)=0\\Hence,\\a=4,\ b=8,\ and\ c=4.](https://tex.z-dn.net/?f=Hence%2C%5C%5C4w%5E2%2B8w%2B4%3D0%5C%5C4%28w%5E2%29%2B8%28w%29%2B4%28w%5E0%29%3D0%5C%5CHence%2C%5C%5Ca%3D4%2C%5C%20b%3D8%2C%5C%20and%5C%20c%3D4.)
![Now,\\We\ can\ decide\ the\ nature\ of\ roots\ the\ quadratic\ equation\ has,\ by\ looking\\ at\ its\ Discriminant.\\Hence,\\Lets\ first\ find\ the\ Discriminant\ for\ our\ equation:\\](https://tex.z-dn.net/?f=Now%2C%5C%5CWe%5C%20can%5C%20decide%5C%20the%5C%20nature%5C%20of%5C%20roots%5C%20the%5C%20quadratic%5C%20equation%5C%20has%2C%5C%20by%5C%20looking%5C%5C%20at%5C%20its%5C%20Discriminant.%5C%5CHence%2C%5C%5CLets%5C%20first%5C%20find%5C%20the%5C%20Discriminant%5C%20for%5C%20our%5C%20equation%3A%5C%5C)
![We\ know\ that,\\Discriminant=b^2-4ac\\\\Substituting\ a=4, b=8, c=4\ in\ the\ Discriminant\ Formula,\ we\ get:\\8^2-4*4*4\\=64-64\\=0\\Hence,\\Discriminant=0](https://tex.z-dn.net/?f=We%5C%20know%5C%20that%2C%5C%5CDiscriminant%3Db%5E2-4ac%5C%5C%5C%5CSubstituting%5C%20a%3D4%2C%20b%3D8%2C%20c%3D4%5C%20in%5C%20the%5C%20Discriminant%5C%20Formula%2C%5C%20we%5C%20get%3A%5C%5C8%5E2-4%2A4%2A4%5C%5C%3D64-64%5C%5C%3D0%5C%5CHence%2C%5C%5CDiscriminant%3D0)
![We\ also\ know\ that\ if,\\D>0, The\ equation\ forms\ 2\ distinct\ real\ roots.\\D=0,The\ equation\ forms\ only\ one\ real\ root\ exactly\ at\ the\ x-axis.\\D](https://tex.z-dn.net/?f=We%5C%20also%5C%20know%5C%20that%5C%20if%2C%5C%5CD%3E0%2C%20The%5C%20equation%5C%20forms%5C%202%5C%20distinct%5C%20real%5C%20roots.%5C%5CD%3D0%2CThe%5C%20equation%5C%20forms%5C%20only%5C%20one%5C%20real%5C%20root%5C%20exactly%5C%20at%5C%20the%5C%20x-axis.%5C%5CD%3C0%2C%5C%20The%5C%20equation%5C%20forms%5C%20Imaginary%2FComplex%5C%20Roots%5C%20or%5C%20basically%5C%20no%5C%20real%5C%20roots.)
![Here,\\As\ D=0,\\The\ equation\ forms\ only\ one\ Real\ root\ or\ has\ only\ one\ solution.](https://tex.z-dn.net/?f=Here%2C%5C%5CAs%5C%20D%3D0%2C%5C%5CThe%5C%20equation%5C%20forms%5C%20only%5C%20one%5C%20Real%5C%20root%5C%20or%5C%20has%5C%20only%5C%20one%5C%20solution.)
I can help, just multiply it if it is (2^3)^4 is 3x4=12 so it’s 2^12, that’s just an example anyway just tell me the problem and I’ll help or tell you the answer, whatever you need :)
Answer:
35000
Step-by-step explanation: