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Flura [38]
3 years ago
10

Round 9,287 to the nearest ten

Mathematics
2 answers:
Maslowich3 years ago
8 0
9,290 because 7 is more than 5 so you round up
aleksandr82 [10.1K]3 years ago
5 0
The nearest one is 7.
Thus, you must round up that 8 to get 9,which gives you 9287 => 9290 (to the nearest 10).
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What is the substitution of -6x-8y=-20 and x+6y=-6
ale4655 [162]

Substitution doesn't work for this, but elimination does.

-6x-8y=-20 +6( x+6y=-6)

-6x-8y=-20 + 6x+36y=-36

-6x and 6x cancel each other, add -8 and 36 to get 28, and -20 and -36 to get -56.

28y=-56

divide by 28 on both sides.

Y= -2

Then substitute y into one of the equations.

x+6(-2)=-6

x-12=-6

x=6

The ordered pair is (6,-2).

5 0
3 years ago
Read 2 more answers
Is 3.7 an integer<br> Need help on my math homework plz help
Finger [1]
An integer is a number that is not a fraction so no 3.7 is not an integer
4 0
3 years ago
-5(4b+ 7) = distributive property
vova2212 [387]

Answer:

-20b-35

Step-by-step explanation:

8 0
2 years ago
6 and<br> Find the value of this expression if x<br> y--1.<br> xy2<br> -5
zysi [14]

Answer:

y = 5;  x = 1/5

Step-by-step explanation:

xy = 1    ----->  x = 1/y

xy^2 = 5 -----> 1/y * y^2 = 5

y^2 / y = 5

y = 5

5x = 1

x = 1/5

Hope this Helps!

5 0
3 years ago
Consider the following hypothesis test: H0: μ1 - μ2 = 0 Ha: μ1 - μ2 ≠ 0 There are two independent samples taken from the two pop
nlexa [21]

Answer:

The value of the test statistic is z = 1.78

Step-by-step explanation:

Before finding the test statistic, we need to understand the central limit theorem and subtraction of normal variables.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Subtraction between normal variables:

When two normal variables are subtracted, the mean is the difference of the means, while the standard deviation is the square root of the sum of the variances.

Sample 1:

\mu_1 = 110, s_1 = \frac{7.2}{\sqrt{81}} = 0.8

Sample 2:

\mu_2 = 108, s_2 = \frac{6.3}{\sqrt{64}} = 0.7875

The test statistic is:

z = \frac{X - \mu}{s}

In which X is the sample mean, \mu is the value tested at the null hypothesis, and s is the standard error.

0 is tested at the null hypothesis:

This means that \mu = 0

Distribution of the difference:

X = \mu_1 - \mu_2 = 110 - 108 = 2

s = \sqrt{s_1^2+s_2^2} = \sqrt{0.8^2+0.7875^2} = 1.1226

What is the value of the test statistic?

z = \frac{X - \mu}{s}

z = \frac{2 - 0}{1.1226}

z = 1.78

The value of the test statistic is z = 1.78

5 0
3 years ago
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