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3 years ago

8X +6Y+4 Y=-3X+9 using substitution what numbers are the variables X and Y

Mathematics

1 answer:

Svetach [21]3 years ago

6 0

Answer:

(5,6)

Step-by-step explanation:

8X +6Y=4

Y=-3X+9

Substitute the second equation into the first. Every place you see y put -3x+9)

8x +6(-3x+9)=4

Distribute

8x-18x +54 = 4

Combine like terms

-10x +54 = 5

Subtract 54 from each side

-10x +54-54=4-54

-10x = -50

Divide by -10

-10x/-10 = -50/-10

x= 5

Now we need to find y

y = -3x+9

y = -3(5) +9

y = -15+9

y= 6

(5,6)

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What is the value of k in the equation StartFraction k Over 3 EndFraction minus 5 = 34?

12345 [234]

$\huge\text{$k=\boxed{117}$}$

$\displaystyle\frac{k}{3}-5=34$

To find the value of $k$ , we need to isolate it on one side of the equation. Add $5$ to both sides of the equation, then multiply both sides of the equation by $3$ .

$\displaystyle\begin{aligned}\frac{k}{3}-5+5&=34+5\\\frac{k}{3}&=39\\\frac{k}{3}*3&=39*3\\k&=\boxed{117}\end{aligned}$

4 0

3 years ago

Read 2 more answers

One gram of protein contains 4 calories. One gram of fat contains 9 calories. A snack has 60 calories from p grams of protein an

nikitadnepr [17]

Answer:

1.5 grams of protein.

Step-by-step explanation:

The equation that represents the relationship between protein and fat is as follows :

4p + 9f = 60 ....(1)

We need to find the grams of protein are there if there are 6 grams of fat in the snack.

Put f = 6 in the above equation (1).

4p + 9(6)= 60

4p + 54 = 60

Subtract 54 to the both sides,

4p + 54-54 = 60-54

4p = 6

⇒ p = 1.5 grams

It means the snack contains 1.5 grams of protein.

4 0

3 years ago

Show both decimal places (5.06).

lilavasa [31]

a. the cost of a call for six minutes is 0.70.

b.the cost of a 14-minute call is 2.62.

c.the cost of a 9 ½2-minute call is 1.66.

given that

rate schedule for an m-minute call from any of its pay phones 0.70.

c(m) = 0.70 when m<=6

c(m) = 0.70+ 0.24(m-6) when m>6 & m is an integer

c(m) = 0.70+0.24((m-6)+1) when m>6 & m is not an integer.

a. to find the cost of a call for six minutes.

already given that c(m) =0.70 when m=6.

Therefore, the cost of a call for six minutes is 0.70.

b. to find the cost of a 14-minute call.

according to given information

$c(14) = 0.70 + 0.24(m - 6) \\ c(14) = 0.70 + 0.24(14 \: - 6) \\c(14) = 0.70 + (0.24 \times 14) - (0.24 \times 6) \\c(14) = 0.70 + (3.36 - 1.44) \\ c(14) = 0.70 + 1.92 \\ c(14) = 2.62$

Therefore,the cost of a 14-minute call is 2.62.

c.to find the cost of a 9 ½2-minute call

according to given information

$c(9 \frac{1}{2} 2) = 0.70 + 0.24((9 \frac{1}{2} 2 - 6) + 1) \\ c(9 \frac{1}{2} 2) = 0.70 + 0.24((9 - 6) + 1) \\ c(9 \frac{1}{2} 2) = 0.70 + 0.24(3+ 1) \\ c(9 \frac{1}{2} 2) = 0.70 + 0.24(4) \\ c(9 \frac{1}{2} 2) = 0.70 + 0.96 \\ c(9 \frac{1}{2} 2) = 1.66$