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3 years ago

14

The big wheel could have a 52 inch diameter and the small wheel could have an 18 inch diameter, what is the circumference of the

big wheel?

1 answer:

kati45 [8]3 years ago

6 0

26 inch diameter because 52 divided by 2 is 26.

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Connor have six employees and Bob 41 uniforms for them if you wanted to give them the same number of uniforms so he doesn't have

bagirrra123 [75]

It will be 6 to each person because 6x6 is 36 if u do 6x7 it will be 42 and it said 41 t-shirts not 42

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2 years ago

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Can someone pls help me? :)

erastova [34]

Step-by-step explanation:

1 t=16/21

2.m=2

3.n=13/7

4.a=2

5.x=6/17

6.x=15

7.s=21/4

8. t=7/3

9. s=1

10. s=6/61

11. x=1/3

12. r=27/16

13. c=−1

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2 years ago

Please find the exact length of the midsegment of trapezoid JKLM with vertices J(6, 10), K(10, 6), L(8, 2), and M(2, 2). Thank y

I am Lyosha [343]

Answer:

the exact length of the midsegment of trapezoid JKLM = $\mathbf{ = 3 \sqrt{5} }$ i.e 6.708 units on the graph

Step-by-step explanation:

From the diagram attached below; we can see a graphical representation showing the mid-segment of the trapezoid JKLM. The mid-segment is located at the line parallel to the sides of the trapezoid. However; these mid-segments are X and Y found on the line JK and LM respectively from the graph.

Using the expression for midpoints between two points to determine the exact length of the mid-segment ; we have:

$\mathbf{ YX = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2} }$

$\mathbf{ YX = \sqrt{(8-5)^2+(8-2)^2} }$

$\mathbf{ YX = \sqrt{(3)^2+(6)^2} }$

$\mathbf{ YX = \sqrt{9+36} }$

$\mathbf{ YX = \sqrt{45} }$

$\mathbf{ YX = \sqrt{9*5} }$

$\mathbf{ YX = 3 \sqrt{5} }$

Thus; the exact length of the midsegment of trapezoid JKLM = $\mathbf{ = 3 \sqrt{5} }$ i.e 6.708 units on the graph

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2 years ago

A baby elephant that is 4 ft tall casts a

Kazeer [188]

Answer:

15 ft

Step-by-step explanation:

10/4

=2.5

6*2.5

=15 ft

PLS GIVE BRAINLIEST

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2 years ago

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True or False: The value of r represents the reference angle when plotting a point in polar coordinates.

Anarel [89]

The answer to the statement above would be false. The value of r does not represent the reference angle when plotting a point in polar coordinates. Instead, it represents the polar distance instead of the angle. The reference angle is represented by <em>t.</em>

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2 years ago

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